You were charged interest of $6.31 for purchases (near section 8) why?

2/35possible outcomes:5*7=35fresh or apple = 22/35

Answer:

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

Next, differentiate with respect to 't'

By factoring out i, j, and k terms, we arrive at:

Answer:

Step-by-step explanation:

The graph can take on three forms as displayed in the figure.

(a) having no intersections

(b) having a single point of intersection (tangency)

(c) having two points of intersection.

Consequently, the maximum number of intersections that these graphs can yield is 2, as illustrated in figure (c).

First, we need to identify the integers between 301 and 400 that are divisible by 4. The initial number is 304, which is the first multiple of 4 in that range. The sequence formed is 304, 308, 312,...,400, creating an arithmetic progression (AP). To determine how many such integers exist, we utilize the AP formula.

Let x represent the amount invested at 6% and y the amount at 9%.
The equation x+y=8,500 leads to x=8500-y.
For the interest rates, we know 6%=0.06 and 9%=0.09.
The equation becomes 0.06x + 0.09y=667.5 (substituting for x to use only y).
Expanding yields: 0.06(8500-y)+0.09y=667.5.
Solving this gives us 510-0.06y+0.09y=667.5 (-510).
This simplifies to 0.03y=117.5 (/0.03), yielding y=$3916.67 for the 9% investment.
Thus, X=8500-Y results in x=$4583.33 for the 6% investment.