Result:
6.1°; 425.86 m.
Step-by-step breakdown:
The information provided states that the airplane is at an altitude of 5.7 miles above ground level, while the "radius of Earth is about 4000 miles." Thus,
θ = 2 × cos^-1 (a/ (a + b)), where a = 4000 miles, and b = 5.7 miles.
θ = 2 × cos^-1 (4000/ (4000 + 5.7)) = 6.1°.
To calculate the distance in meters:
Change in distance = 6.1° /360° × 2π × 4000 miles = 425.86 meters.
Consequently, BD⌢ measures at 6.1° and the distance corresponding to this section of Earth is 425.86 meters.
<span>The admission price for the art museum is $9.75 per ticket.
</span><span>Compared to science museum tickets, art museum tickets are pricier.
</span>
This was verified through my testing.
To demonstrate:
The angle drawn within a semicircle forms a right angle.
According to the inscribed angle theorem, the angle θ that is inscribed in a circle is half of the measure of the central angle. Thus, in a semicircle, the inscribed angle is half of 180 degrees, resulting in 90 degrees, which is a right angle. <span />
This explanation follows: The query lacks completeness; please refer to the complete question in the provided attachment. The curve described is represented by the quadratic equation, y = x². If the curve moves downwards by 2 units, the equation for the new curve becomes y = x² - 2. Shifting the curve 2 units to the left results in the equation y = (x + 2)². Conversely, moving the curve 2 units to the right transforms it to y = (x - 2)². Lastly, if shifted upwards by 2 units, the equation will be y = x² + 2.
