Answer:
Nina's speed in MPH: 12.706 miles per hour
Nina is quicker than Sophia.
Step-by-step explanation:
To solve this problem, we will convert feet per second to miles per hour and subsequently compare Nina's speed to that of Sophia's.
Nina rides at 63360 feet in 3400 seconds. To perform this conversion, we know that there are 5280 feet in a mile and 3600 seconds in an hour. Applying these conversions, we can calculate the speed in miles per hour.
(63360 feet / 3400 seconds) * (1 mile / 5280 feet) * (3600 seconds / 1 hour) = 12.706 miles per hour.
Thus, it follows that Nina rides her bike at a rate of 12.706 miles per hour, whereas Sophia rides her bicycle at a rate of 10 miles per hour.
This indicates that Nina rides faster than Sophia by 2.706 miles per hour (12.706 - 10).
Cheers.
The correct answer is "His teacher advised it because he did not have time to tutor Euler privately." I completed the assignment and got it correct.
The temperature increased by 29°C, which indicates a positive change of 29. Then, it decreased by 29°C, reflecting a negative change. The average temperature experienced equal increases and decreases, leading to identical absolute values and resulting in a difference of 0.
Answer:
Step-by-step explanation:
Considering the equation
Sin(5x) = ½
5x = arcSin(½)
5x = 30°
Then,
The general formula for sin is
5θ = n180 + (-1)ⁿθ
Dividing throughout by 5
θ = n•36 + (-1)ⁿ30/5
θ = 36n + (-1)ⁿ6
The solution range is
0<θ<2π which means 0<θ<360
First solution
When n = 0
θ = 36n + (-1)ⁿθ
θ = 0×36 + (-1)^0×6
θ = 6°
When n = 1
θ = 36n + (-1)ⁿ6
θ = 36-6
θ = 30°
When n = 2
θ = 36n + (-1)ⁿ6
θ = 36×2 + 6
θ = 78°
When n =3
θ = 36n + (-1)ⁿ6
θ = 36×3 - 6
θ = 102°
When n=4
θ = 36n + (-1)ⁿ6
θ = 36×4 + 6
θ = 150
When n=5
θ = 36n + (-1)ⁿ6
θ = 36×5 - 6
θ = 174°
When n = 6
θ = 36n+ (-1)ⁿ6
θ = 36×6 + 6
θ = 222°
When n = 7
θ = 36n + (-1)ⁿ6
θ = 36×7 - 6
θ = 246°
When n =8
θ = 36n + (-1)ⁿ6
θ = 36×8 + 6
θ = 294°
When n =9
θ = 36n + (-1)ⁿ6
θ = 36×9 - 6
θ = 318°
When n =10
θ = 36n + (-1)ⁿ6
θ = 36×10 + 6
θ = 366°
When n = 10 surpasses the θ range
Thus, the solutions range from n =0 to n=9
Therefore, there are 10 solutions within the interval 0<θ<2π
Part 1) The radius of the circle is r=17 units. Part 2) The points (-15,14) and (-15,-16) are situated on this circle. Step-by-step explanation: Step 1 Find the radius of the circle. We know that the distance from the center of the circle to any point on its circumference equals the radius of the circle. The formula to determine the distance between two points is equal to......we have (-7, -1) and (8, 7) substitute... Step 2 Determine the y-coordinate of point (-15,y). The standard form of the circle's equation is given by... where (h,k) represents the center, and r is the radius. Replace the values, substituting x=-15 in the equation... square root both sides... ultimately, we find two solutions: point (-15,14) and point (-15,-16) refer to the attached figure for a clearer understanding of the problem.
