Write a program that takes in a positive integer as input, and outputs a string of 1's and 0's representing the integer in binar

#include <stdio.h>

#include <stdlib.h>

int main ()

{

   int n, i = 1, k;

   int j;

   int binary[10];

   printf ("Enter Number \t:");

   scanf ("%d", &n);

   while (n > 0) {

       binary[i] = n % 2;

       n = n / 2;

       i = i + 1;

       k = i;

   }

   for (j = k-1; j > 0; j--)

       printf ("%d", binary[j]);

}

Further explanation

Converting numbers means changing a number into a different format that keeps the same value. Transforming decimal to binary means changing the decimal digits into binary digits of identical value.

The process involves dividing the decimal number by 2, recording the remainder each time while rounding down until zero is reached. The remainders are then read backwards to produce the binary number.

For example, converting 50 decimal to binary:

50/2=25 remainder 0

25/2=12 remainder 1

12/2=6 remainder 0

6/2=3 remainder 0

3/2=1 remainder 1

1/2=0 remainder 1

Answer:

// Java Code

import java.io.*;

class Binary {

// method to convert integer to binary

static void convert(int num) {

int bin[] = new int[32];

int i=0,j;

while (num > 0) {

bin[i] = num % 2;

num = num / 2;

i++;

}

System.out.println("Number in Binary is");

for (j=i-1;j>=0;j--)

System.out.print(bin[j]);

}

public static void main(String[] args)throws IOException {

InputStreamReader x = new InputStreamReader(System.in);

BufferedReader inp = new BufferedReader(x);

int n;

System.out.println("Enter the decimal number to convert to binary");

n=Integer.parseInt(inp.readLine());

convert(n);

}

}

Explanation:

The program reads an input, creates an array for 32-bit binary numbers, repeatedly divides the input by 2 storing remainders, then prints the remainders in reverse order.

Output:

Enter the decimal number to convert to binary

6

Number in Binary is

110