The outcome is "
GK=37, GH=14, and JK=19".The problem references a missing attachment file, thus please find it attached.
The provided values are:
GJ=4x+2
HK=6x-1
Given GK =37
Need to calculate:
HJ=?
From GK: GK = GJ+JK yields GJ+(HK-HJ)
= 4x+2+((6x-1)-x) yields
9x+1...(a)Substituting (a) into the equation gives: 9(4)+1 yields 37 solves to x=4... for answer (b) and (c). Substituting x=4 yields:
GH=14 and JK=19.
y2 = C1xe^(4x) Step-by-step explanation: Knowing that y1 = e^(4x) satisfies the differential equation y'' - 8y' + 16y = 0, we need to derive the second solution y2 using the reduction of order technique. Let y2 = uy1. Since y2 is a solution to the differential equation, it holds that y2'' - 8y2' + 16y2 = 0. By substituting for y2, its derivatives become y2 = ue^(4x), y2' = u'e^(4x) + 4ue^(4x), and y2'' = u''e^(4x) + 8u'e^(4x) + 16ue^(4x). Plugging these into the differential equation gives us u''e^(4x) = 0. Let w = u', so w' = u''. This results in w' e^(4x) = 0, leading to w' = 0. Integrating gives w = C1. Since w = u', this implies u' = C1, and integrating once more results in u = C1x. Therefore, y2 = ue^(4x) becomes y2 = C1xe^(4x), which is the second solution.
-2(5,6)-40 That should cover it.
He rents the car for d days, but receives two days at no cost, meaning he only needs to pay for d - 2 days.
Each day's rental costs $45, so for d - 2 days, the cost is 45(d - 2). The total expenditure amounts to $315, leading to the equation
45(d - 2) = 315
Now, let's solve for d, the number of days rented.
45(d - 2) = 315
45d - 90 = 315
45d = 405
d = 9
He rented the car for 9 days.
Answer:
Shane must have gathered a minimum of 911 cans.
Step-by-step explanation:
Let S represent the number of cans Shane collected.
Since Abha collected 178 more cans, her total is S + 178.
The combined total should be at least 2000:
S + (S + 178) ≥ 2000
2S + 178 ≥ 2000
2S ≥ 2000 - 178
2S ≥ 1822
S ≥ 911
Therefore, Shane must have collected at least 911 cans.
