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natka813
9 days ago
8

the local volleyball team hosts a concession stand to raise money. They can spend $120 to purchase popcorn, candy, and drinks. t

hey purchase 95 bags of popcorn at $0.75 each and 35 bags of candy at $1.20 each. how much money does the volleyball team have left to spend on drinks?
Mathematics
1 answer:
zzz [12.3K]9 days ago
7 0
To address this inquiry, I formulated an equation:
0.75x + 1.20y = 120
0.75(95) + 1.20(35) = 120
Next, I performed the multiplication:
71.25 + 42 = 120
Now to verify:
71.25 + 42 = 113.25
The result: 120 - 113.25 = $6.75 Hope this is useful

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Sandra deposited $2,500 into a simple interest account. She earned $75 in interest after 1 year. Ron deposited $8,000 into an ac
PIT_PIT [12445]

Answer:

the interest amount totals $240

Step-by-step explanation:

I hope this is helpful.

6 0
17 days ago
If speed varies inversely as the time it takes to drive and Kris takes 5 hours driving at 55 mph, what speed will Martin need to
AnnZ [12381]

Response:

55 mph. All options are incorrect.

Detailed explanation:

When speed changes inversely with the time taken, it can be expressed as v ∝ 1/t, where:

v represents speed,

t refers to the time taken.

This leads to;

v = k/t, with k being a constant of proportionality.

Given that Kris takes 5 hours traveling at 55 mph, we replace v with 55 mph and t with 5 hours in the equation to find k as follows:

55 = k/5

Cross-multiplying yields:

k = 55 * 5

k = 275

To determine the speed Martin needs to drive for 5 hours, we substitute k = 275 and t = 5 back into the original equation v = k/t as follows:

v = 275/5

v = 55 mph

Thus, we conclude that in order to travel for 5 hours, Martin must also drive at 55 mph.

3 0
10 days ago
The standard kilogram (fig. 1.1a) is a platinum–iridium cylinder 39.0 mm in height and 39.0 mm in diameter. what is the density
AnnZ [12381]
The volume of a cylinder can be determined using the formula pi*h*d^2/4, which leads us to V = pi*(39 mm)(39 mm)^2 / 4 = 46,589 mm^3. Dividing the mass of 1 kg by the volume of 46,589 mm^3 results in a density of 2.1464 x 10^-5 kg/mm^3. Typically, density is expressed in kg/m^3, so we convert this by multiplying by 1x10^9, yielding a density of 21,464 kg/m^3.
6 0
26 days ago
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
babunello [11817]

Answer:

To find the number of genuine solutions for a system of equations consisting of a linear equation and a quadratic equation

1) With two variables, say x and y, rearrange the linear equation to express y, then substitute this y in the quadratic equation

After that, simplify the resulting equation and determine the number of real roots utilizing the quadratic formula, x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a} for equations of the type 0 = a·x² - b·x + c.

When b² exceeds 4·a·c, two real solutions emerge; if b² equals 4·a·c, there will be a single solution.

Step-by-step explanation:

3 0
1 month ago
Finally, suppose m1→∞, while m2 remains finite. what value does the the magnitude of the tension approach?
AnnZ [12381]
The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>
5 0
1 month ago
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