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sergey
1 month ago
15

Two is a zero of the equation x3−x2−14x+24=0. Which factored form is equivalent to the equation?

Mathematics
1 answer:
Inessa [12.5K]1 month ago
3 0
The answer to your question is: letter A. The polynomial equation x³ - x² - 14x + 24 = 0 indicates that two is a zero. Therefore, we divide the polynomial by 2. Using synthetic division, we have: 1, -1, -14, +24 using 2. The process yields 1, 1, -12, and 0. Thus, the result is x² + x - 12 = 0. We then need to factor this polynomial, identifying two numbers that multiply to -12 and sum to +1. These numbers are +4 and -3. Therefore, we determine that (x + 4)(x - 3) = 0. Ultimately, we arrive at the factored form (x + 4)(x - 3)(x - 2) = 0.
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Tracie's bus moves towards home at an average pace of one-half mile for every minute.

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A certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of awriting
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Answer:

a) Null hypothesis:\mu \geq 10

Alternative hypothesis:\mu < 10

b) p_v =P(t_{17}

Given that the p-value is lower than the significance threshold in this situation, we have sufficient grounds to reject the null hypothesis.

c) p_v =P(t_{17}

In this case, since the p-value exceeds the significance threshold, we have adequate evidence to FAIL to reject the null hypothesis.

d) p_v =P(t_{17}

Here again, with the p-value being less than the significance level, we can reject the null hypothesis.

Step-by-step explanation:

1) Provided data and references

\bar X represents the average of the samples

s denotes the standard deviation of the samples

n=18 indicates the number of samples

\mu_o =10 is the value we are examining

\alpha defines the significance level for the test.

t represents the specific statistic of interest

p_v indicates the p-value relevant to the test (the variable of concern)

Define the null and alternative hypotheses.

To assess if the true mean is at least 10 hours, we must set up a hypothesis:

Part a

Null hypothesis:\mu \geq 10

Alternative hypothesis:\mu < 10

If we consider the sample size being less than 30 and the population deviation unknown, it’s more appropriate to use a t-test to compare the actual mean with the reference value, calculated as:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)

Part b

In this scenario t=-2.3, \alpha=0.05

Initially, we need to calculate the degrees of freedom df=n-1=18-1=17

Since this is a left-tailed test, the p-value is determined by:

p_v =P(t_{17}

In this instance, with the p-value being less than the significance level, we have sufficient evidence to reject the null hypothesis.

Part c

For this situation t=-1.8, \alpha=0.01

We need to find the degrees of freedom df=n-1=18-1=17

For the left-tailed test, the p-value is given by:

p_v =P(t_{17}

In this case, since the p-value is above the significance level, we have enough grounds to FAIL to reject the null hypothesis.

Part d

For this case t=-3.6, \alpha=0.05

Firstly, we find the degrees of freedom df=n-1=18-1=17

Since we are conducting a left-tailed test, the p-value is calculated as:

p_v =P(t_{17}

Here, with the p-value being lower than the significance threshold, we can reject the null hypothesis.

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Alejandro surveyed his classmates to determine who has ever gone surfing and who has ever gone snowboarding. Let A be the event
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Answer:

\text{A and B are independent events}, P(A|B)=P(A)=0.16

Step-by-step explanation:

To establish independence between two events, we must understand the concept of independence:

Events are deemed independent if P(A|B)=P(A), which means that the occurrence of one does not influence the probability of the other event.

In this situation, the only selection that aligns with the independence criterion is P(A|B)=P(A)=0.16. Other options do not comply with the independent events definition.

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