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mixas84
9 days ago
15

Which expression is equivalent to (3m^-2n)^-3/6mn^-2? Assume m=0, n=0.

Mathematics
2 answers:
Zina [11.9K]9 days ago
8 0
The result simplifies to m^5/162n
Solving:
(3m^-2 n)^-3 / 6mn^-2
You will need to apply the power of -3 to both m and n and distribute it accordingly. m^-2*-3 n^-3 / 6mn^-2
And utilize the product and quotient rules: m^6 n^2/ 3^3 * 6 * m * n^3
Finally, simplify the expression
m^5/162n

Thus, the final answer is
m^5/162n
Inessa [12.1K]9 days ago
8 0
This is the solution:

(3m^-2 n)^-3 / 6mn^-2
For the first step: apply the power distribution3^-3 m^-2*-3 n^-3 / 6mn^-2
In the second step: utilize the product and quotient rulesm^6 n^2/ 3^3 *6*m*n^3
Lastly, simplify the expressionm^5/162n
The conclusive answer is m^5/162n

Hope this aids you.:)
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Which formula can be used to describe the sequence? -2/3,-4,-24,-144...
lawyer [12109]

The formula that describes the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Step-by-step explanation:

The nth-term formula for a geometric sequence is a_{n}=a(r)^{n-1}, where

  • a represents the first term of the sequence
  • r signifies the common ratio between any two consecutive terms
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∵ The sequence is \frac{-2}{3}, -4, -24, -144,.......

∵ The first term is \frac{-2}{3}

∵ The second term is -4

∴ \frac{-4}{\frac{-2}{3}}=6

∵ The third term is -24

∴ \frac{-24}{-4}=6

∵ The fourth term is -144

∴ \frac{-144}{-24}=6

∵  \frac{a_{2}}{a_{1}} = \frac{a_{3}}{a_{2}} =  \frac{a_{4}}{a_{3}} = 6

∴ There is a consistent ratio between two consecutive terms

∴ The sequence qualifies as a geometric sequence

∵ The formula for the nth term of the geometric sequence is a_{n}=a(r)^{n-1}

∵ a = \frac{-2}{3}

∵ r = 6

∴ The equation for the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

The formula that can be employed to outline the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Learn more:

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