Answer:
6.79 miles
Step-by-step explanation:
Consider triangle ABC where A marks the starting point and C indicates the end point.
|AB|=5.2 miles
|BC|=3.0 miles
∠ABC = 90 + 75 = 165°
We're given two side lengths and an angle that is not opposite to either side.
The approach to resolve this scenario is known as the Cosine Rule.
Each side opposite an angle is designated by the corresponding lowercase letter.
The Cosine Rule asserts that:
b² = a² + c² - 2acCosB
|AC|²=3² + 5.2² - (2 × 5.2 × Cos 165°)
|AC|²=9 + 27.04 + 10.05
|AC|²=46.09
|AC|=√46.09=6.79 miles
Thus, the straight-line distance from A to C measures 6.79 miles
The formula representing this scenario is 
The answer to this formula is 
Initially, you need to formulate the equation.

Next, simplify the expressions.

Afterwards, subtract 5.7 from both sides.

Lastly, divide both sides by 5

The function's constant term is 5. Step-by-step explanation: we have where b represents the y-intercept or the constant term of the function. The x-intercept indicates the value of x when the function equals zero. Thus, for x = -3, f(x) = 0 and for x = -5, f(x) = 0. Substitute either of the intercepts into the function. Check the other intercept as well. For x = -5, this is proven to be true. Hence, the consistent term in the function is 5.
The missing value associated with
is 
Explanation:
The provided equation for the table is 
This table consists of 2 columns and 5 rows.
<pconsequently it="" states="">
x y
-2 10
-1 ---
0 2
1 -2
2 -6
To find the value for y when
The value of y can be ascertained by substituting
into the equation 
<pthus we="" determine="">

<pmultiplying the="" term="" within="" brackets="" yields="">

<psumming the="" terms="" we="" find="">

<pso the="">value of y when
is 6.Hence, the value for
is 
</pso></psumming></pmultiplying></pthus></pconsequently>
There are 50 pairs of whole numbers that can add up to 99. To clarify, consider the combinations: 0 + 99, 1 + 98, 2 + 97, and so on, up to 49 + 50. This observation indicates that counting all combinations would result in 50 pairs of distinct whole numbers that sum to 99. I hope this response assists you!