In a cash drawer there is $125 in $5 and $10 bills. The number of $10 bills is twice the number of $5 bills. How many of each ty

Let x denote the count of $5 bills and y signify the count of $10 bills. It can be stated that "the number of $10 bills is twice the number of $5 bills." Thus, y is 2 times x. We can formulate an equation, y = 2x (equation 1). The total value of all bills amounts to $125, allowing us to create another equation: 5*(number of $5 bills) + 10*(number of $10 bills) = 125. That leads to the equation 5(x) + 10(y) = 125 (equation 2). By substituting y = 2x into equation 2, we get 5(x) + 10(2x) = 125. This simplifies to 5x + 20x = 125. Combining like terms yields 25x = 125. Dividing both sides by 25 results in x = 5. By substituting x = 5 in the first equation, we find y = 2(5) = 10. Consequently, there are 5 $5 bills and 10 $10 bills.