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Setler79
8 days ago
11

The path of a total solar eclipse is modeled by f (t )equals 0.00223 t squared minus 0.558 t plus 41.395​, where​ f(t) is the la

titude in degrees south of the equator at t minutes after the start of the total eclipse. What is the latitude closest to the​ equator, in​ degrees, at which the total eclipse will be visible.
Mathematics
1 answer:
Leona [12.6K]8 days ago
7 0

Response:

Thus, the latitude nearest to the equator is approximately 6.49°.

Step-by-step rationale:

The solar eclipse path is modeled by

f(t)=0.00223t^2-0.558t+41.395

where f(t) denotes latitude in degrees south of the equator corresponding to t minutes.

We acknowledge that

The minimum or maximum of a function represented by y(t) =at²+bt+c

occurs when t=-\frac{b}{2a}

Here, a= 0.00223, b= - 0.558, and c= 41.395.

Thus, the minimum of f(t)

occurs at t=-\frac{( - 0.558)}{2\times 0.00223}

           =125.11

Consequently, the latitude closest to the equator can be determined as

f(125.11)=0.00223(125.11)²-0.558×125.11+41.395

            ≈6.49

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