Answer:
Step-by-step explanation:
Considering the equation
Sin(5x) = ½
5x = arcSin(½)
5x = 30°
Then,
The general formula for sin is
5θ = n180 + (-1)ⁿθ
Dividing throughout by 5
θ = n•36 + (-1)ⁿ30/5
θ = 36n + (-1)ⁿ6
The solution range is
0<θ<2π which means 0<θ<360
First solution
When n = 0
θ = 36n + (-1)ⁿθ
θ = 0×36 + (-1)^0×6
θ = 6°
When n = 1
θ = 36n + (-1)ⁿ6
θ = 36-6
θ = 30°
When n = 2
θ = 36n + (-1)ⁿ6
θ = 36×2 + 6
θ = 78°
When n =3
θ = 36n + (-1)ⁿ6
θ = 36×3 - 6
θ = 102°
When n=4
θ = 36n + (-1)ⁿ6
θ = 36×4 + 6
θ = 150
When n=5
θ = 36n + (-1)ⁿ6
θ = 36×5 - 6
θ = 174°
When n = 6
θ = 36n+ (-1)ⁿ6
θ = 36×6 + 6
θ = 222°
When n = 7
θ = 36n + (-1)ⁿ6
θ = 36×7 - 6
θ = 246°
When n =8
θ = 36n + (-1)ⁿ6
θ = 36×8 + 6
θ = 294°
When n =9
θ = 36n + (-1)ⁿ6
θ = 36×9 - 6
θ = 318°
When n =10
θ = 36n + (-1)ⁿ6
θ = 36×10 + 6
θ = 366°
When n = 10 surpasses the θ range
Thus, the solutions range from n =0 to n=9
Therefore, there are 10 solutions within the interval 0<θ<2π
Take note of the image below
the riverbank requires no fencing due to the river's presence
so the pen's perimeter can be calculated as 2w + l, or w + w + l
thus

derive P(w), set it to zero, locate any critical points, and perform a first-derivative test for minimum values.
The initial height of the candle is 14.8 inches.
Answer:
1. Both directions
2. Only in one direction
Step-by-step explanation:
The reason Statement 1 can occur both ways is that if Bo and Mel are connected, it holds true forward and backward.
The reasoning for Statement 2 being one-directional is that if the sprinklers are operating, then the grass is wet will be valid since it's stating ONLY that the sprinklers are on. If it were to reverse and the grass is wet ONLY because of the sprinklers, then it's incorrect as rain could also cause the grass to be wet. Thus, there are numerous possibilities for the grass being wet, which explains the answers.
The equation representing the circle centered at (-27, 120) that passes through the origin is:

Solution:
The general equation of a circle is expressed as:

Where,
(a, b) denotes the center of the circle
r signifies the radius
Given the center as (-27, 120)
Thus;
a = -27
b = 120
Considering it intersects the origin, meaning (x, y) = (0, 0)
Substituting (a, b) = (-27, 120) and (x, y) = (0, 0) into the equation

Input
= 15129 and (a, b) = (-27, 120) into the equation

Hence, the equation characterizing the circle is determined