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2 months ago

A) La autopista 10 en Haradh, Arabia Saudita, tiene más de 200

Mathematics

1 answer:

Inessa [12.5K]2 months ago

4 0

Pagpapaliwanag hakbang-hakbang:

Dahil hindi tayo nagtakda kung ano ang dapat kalkulahin, puwede rin nating alamin ang oras na kailangan ng sasakyan upang bumyahe sa kalsada.

Bilisan = Distansya / Oras

Oras = Distansya / Bilisan

Inilatag

Distansya = 200 km

Bilisan = 120 km/h

Pagsasubstitute

Oras = 200/120

Oras = 20/12

Oras = 1.67 oras

Kaya, ang oras na kinakailangan ng sasakyan upang makumpleto ang biyahe ay 1.67 oras.

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Find the limits of integration ly, uy, lx, ux, lz, uz (some of which will involve variables x,y,z) so that ∫uyly∫uzlz∫uxlxdxdzdy

Leona [12618]

Answer:

Hello! Your question appears to be missing details; here is the complete version

Ix = 0 Ux = $\sqrt{y-9z^2}$

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Iy = 5 Uy = 10

Step-by-step explanation:

Ix = 0 Ux = $\sqrt{y-9z^2}$

Iz = 0 Uz = $\frac{\sqrt{y} }{3}$

Iy = 5 Uy = 10

This provides a comprehensive solution below

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2 months ago

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1 month ago

The value of an antique chair is expected to increase by 3% every year. If the chair was bought for $1,020 in 2001, find its exp

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Greetings
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2 months ago

Using the U- Substitution u=sqrt(2x), integral form 2-8 dx/ sqrt(2x) + 1 is equivalent to ...

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1 month ago

Suppose that 70% of the orders on a particular website are shipped to the person who is making the order and the remaining 30% a

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Answer:

a) P=0.24

b) P=0.31

c) Not independent.

Step-by-step explanation:

The question is incomplete.

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$P(W\&SOP)=P(SOP)*P(W|SOP)=0.30*0.60=0.24$

W: wrapped

SOP: sent to different individuals

b) What’s the probability that a randomly selected order will be gift wrapped?

$P(W)=P(SOP)*P(W|SOP)+P(SR)*P(W|SR)\\\\P(W)=0.3*0.6+0.7*0.1=0.24+0.07=0.31$

SR: sent to the correct recipient

c) Is gift wrapping independent of the order’s destination? Please provide a statistical justification.

To establish their independence, both conditions must be satisfied:

P(x|y) = P(x), for all values of X and Y.

P(x ∩ y) = P(x) * P(y), for all values of X and Y.

Starting with the second condition.

$P(W\cap SR)=0.1\\\\P(W)*P(SR)=0.31*0.7=0.217\\\\\\P(W\cap SR)\neq P(W)*P(SR)$

This condition is unmet, indicating that these variables are not independent.

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1 month ago