<span>The outcome = probability of choosing exactly 2, 3, 4, or 5 passing plays.
The probability of selecting exactly two passing plays is given by:
(8C2)*(9*8)*
(15*14*13*12*11*10)
/(26*28*.....19)
where:
8C2 represents the combinations of choosing two from 8 and
probability that the first passing play is selected = 9/26
probability that the second passing play is chosen = 10/25, and so forth
you can similarly calculate the other three scenarios and sum them to find the total probability.</span>
C. No, because at least one of the sample sizes exceeds 10 percent of the population.