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Aneli
3 months ago
10

Julio is trying to decide between 4 different vendors for a new IT system. Vendor A is less expensive than Vendor C. Vendor C is

more expensive than Vendor B. Vendor B is less expensive than Vendor D. Vendor D is less expensive than Vendor A. If Julio wants to purchase the least expensive system, which Vendor will he pick?
Computers and Technology
1 answer:
amid [951]3 months ago
8 0

Answer:

Vendor B

Explanation:

By using letters to signify each vendor and the symbol < to indicate which is cheaper, the problem can be summarized as follows: A<C, B<C, B<D, D<A.

These inequalities show that the vendors on the left are less expensive than those on the right, therefore, any vendor appearing on the right in these expressions cannot be the cheapest, ruling out C, D, and A. Thus, the least expensive vendor is B.

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#Write a function called "angry_file_finder" that accepts a #filename as a parameter. The function should open the file, #read i
ivann1987 [1066]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

7 0
1 month ago
Which correctly lists the two elements that make up the empty space in the universe? ice and debris debris and dark matter dark
Rzqust [1037]
The correct response is "dark matter and dark energy and dust." Explanation: In the vast emptiness of the universe, it’s filled with gases and residuals. While humans may perceive the empty space as devoid of contents, it includes plasma hydrogen and helium gases, in addition to various types of dirt and remnants. There's a variety of other materials, but greenhouse gases and dust comprise the majority.
5 0
1 month ago
Read 2 more answers
Identify the four basic categories of hardware in a personal computer system
Harlamova29_29 [1022]
The four primary categories include the motherboard, CPU, graphics card, and RAM.
Please choose Brainliest! Thanks!:)
5 0
1 month ago
Assume a machine during its initial testing phase produces 10 widgets a day. After 10 days of testing (starting on day 11), it b
Harlamova29_29 [1022]

Response:

Python Code:

n = int(input("Days: "))

total = 0

for i in range(1,n+1):

     if i <= 10:

           total += 10

     elif i <= 60:

           total += 40

     elif i <= 99:

           total += 100 - i

print(str(total)+ " widgets")

Clarification:

This line requests user input for the number of days.

n = int(input("Days: "))

This line sets the initial total number of widgets to zero.

total = 0

The subsequent loop calculates total widgets based on the established rules.

for i in range(1,n+1):

     if i <= 10: -> Applies when days are 10 or fewer

           total += 10

     elif i <= 60: -> Applies when days are between 11 and 60

           total += 40

     elif i <= 99: -> Applies when days are under 100

           total += 100 - i

This line outputs the total count.

print(str(total)+ " widgets")

4 0
2 months ago
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