<span><span>1. </span>We have two boxes with weights:
=> 9.4 lb and 62.6 lb.
To find a rough estimate of their total weight, we will round and use compatible numbers.
For 9.4 lbs, rounding gives us 9 lbs
And for 62.6 lbs, it rounds to 63 lbs
=> Adding these two rounded numbers yields:
=> 9 + 63
=> 72, the estimated total is 72.
Let’s verify if this is close to the actual weight
=> 9.4 + 62.6
=> 72</span>
Answer:
The term 6x should actually be 6x²
Step-by-step-explanation:
The illustration referenced, which depicts the multiplication of the trinomial with the binomial, is provided in the image below.
To identify where Chin's multiplication went wrong and to establish the correct expression, we'll analyze each multiplication performed. Therefore, we have:
3x*x² = 3x³
3x*2x = 6x² (the mistake occurred here, as Chin recorded it as 6x in the chart)
3x*4 = 12x
2*x²=2x²
2*2x = 4x
2*4 = 8
Thus, the term 6x should indeed be corrected to 6x²
Begin by creating a system of equations: let 'a' represent the amount Mary earns per student, and 'b' denote her fixed amount. The equations are 90=15a+b (subtracting the lower from the upper equation) and 62=8a+b. From these, we have 90-62=28, leading to 15a-8a=7a, and b cancels itself out. This gives us 7a=28, resulting in a=4. Substituting 'a' into 62=8a+b reveals b=30. Since Lisa earns half of Mary's base, her fixed amount is 15, but she makes twice as much per student, bringing her rate to 8 per student. Thus, we can formulate: m=4c+30 for Mary's earnings, and l=8c+15 for Lisa's. Setting c=20 results in m=110 and l=175, showing that Lisa makes more when teaching a class of 20 students. I trust this information helps.
During an archaeological excavation, an ancient campfire is uncovered. The charcoal is determined to have significantly less than 1/1000 of the standard amount of
. Calculate the minimal age of the charcoal, taking into account that 
Response:
57300 years
Step-by-step breakdown:
Using the relationship of half-life time against fraction, which can be expressed as:

In this context,
N indicates the current atom
represents the initial atom
t signifies the time
denotes the half-life
Since the charcoal was found to contain less than 1/1000 of the typical amount of

.
Thus;

However; the objective is to estimate the minimum age of the charcoal while noting 
this means
, then:



If

Then

Consequently, it can be estimated that the minimum time elapsed is 10 half-lives.
For
, the standard half-life time is 5730 years
Thus, the estimation of the minimum age of the charcoal is 5730 years × 10
= 57300 years