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Zepler
1 month ago
13

In a recent text message survey, 4,000 randomly selected teenagers were asked to cite their favorite Florida college football te

am. Twenty-two of 40 teenagers said the Florida Gators are their favorite team. A 99% confidence interval to estimate the true proportion of teenagers who like the Florida Gators is found to be (0.3474, 0.7526). Which of the following is a correct interpretation of the confidence level? (4 points)
Ninety-nine percent of all samples of this size would yield a confidence interval of (0.3474, 0.7526).

There is a 99% chance that the true proportion of teenagers who like the Florida Gators is (0.3474, 0.7526).

Ninety-nine percent of all the samples of size 4,000 lie in the confidence interval (0.3474, 0.7526).

Ninety-nine percent of the time, the procedure used to generate this interval will capture the true proportion of teenagers who like the Florida Gators.

There is a 99% chance that randomly selected teenagers will be part of the 55% who like the Florida Gators.
Mathematics
1 answer:
lawyer [12.5K]1 month ago
3 0

Answer:

There is a 99% likelihood that the true percentage of teenagers liking the Florida Gators is within (0.3474, 0.7526).

Step-by-step explanation:

A 99% confidence interval estimating the true proportion of teenagers who favor the Florida Gators is calculated as (0.3474, 0.7526).

This indicates that we can be 99% confident the actual proportion of teenagers who like the Florida Gators falls within:

(0.3474, 0.7526)

In simpler terms, there is a 99% chance that the true proportion of teenagers who like the Florida Gators is contained in (0.3474, 0.7526).

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estimate the total weight of two boxes that weigh 9.4 lb and 62.6 lb using rounding and compatible numbers. which estimate is cl
babunello [11817]
<span><span>1.      </span>We have two boxes with weights:
=> 9.4 lb and 62.6 lb.
To find a rough estimate of their total weight, we will round and use compatible numbers.
For 9.4 lbs, rounding gives us 9 lbs
And for 62.6 lbs, it rounds to 63 lbs
=> Adding these two rounded numbers yields:
=> 9 + 63
=> 72, the estimated total is 72.
Let’s verify if this is close to the actual weight
=> 9.4 + 62.6
=> 72</span>



5 0
1 month ago
Chin made an error in his chart showing the multiplication of the binomial by the trinomial. Which change can be made to correct
Inessa [12570]

Answer:

The term 6x should actually be 6x²

Step-by-step-explanation:

The illustration referenced, which depicts the multiplication of the trinomial with the binomial, is provided in the image below.

To identify where Chin's multiplication went wrong and to establish the correct expression, we'll analyze each multiplication performed. Therefore, we have:

3x*x² = 3x³

3x*2x = 6x² (the mistake occurred here, as Chin recorded it as 6x in the chart)

3x*4 = 12x

2*x²=2x²

2*2x = 4x

2*4 = 8

Thus, the term 6x should indeed be corrected to 6x²

7 0
1 month ago
Read 2 more answers
The local skating rink pays marry a fixed rate per pupil plus a base amount to work as a skating instructor. she earns $90 for i
Inessa [12570]
Begin by creating a system of equations: let 'a' represent the amount Mary earns per student, and 'b' denote her fixed amount. The equations are 90=15a+b (subtracting the lower from the upper equation) and 62=8a+b. From these, we have 90-62=28, leading to 15a-8a=7a, and b cancels itself out. This gives us 7a=28, resulting in a=4. Substituting 'a' into 62=8a+b reveals b=30. Since Lisa earns half of Mary's base, her fixed amount is 15, but she makes twice as much per student, bringing her rate to 8 per student. Thus, we can formulate: m=4c+30 for Mary's earnings, and l=8c+15 for Lisa's. Setting c=20 results in m=110 and l=175, showing that Lisa makes more when teaching a class of 20 students. I trust this information helps.
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1 month ago
An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount o
PIT_PIT [12445]

During an archaeological excavation, an ancient campfire is uncovered. The charcoal is determined to have significantly less than 1/1000 of the standard amount of ^{14}\text{C} ​. Calculate the minimal age of the charcoal, taking into account that 2^{10} = 1024

Response:

57300 years

Step-by-step breakdown:

Using the relationship of half-life time against fraction, which can be expressed as:

\dfrac{N}{N_o} = (\dfrac{1}{2})^{\frac{t}{t_{1/2}}

In this context,

N indicates the current atom

represents the initial atomN_o

t signifies the time

denotes the half-lifet_{1/2}

Since the charcoal was found to contain less than 1/1000 of the typical amount of ^{14}\text{C} ​.

Thus;

\dfrac{N}{N_o} = \dfrac{1}{1000}

However; the objective is to estimate the minimum age of the charcoal while noting  2^{10} = 1024

this means 2^{10} = 1024, then:

\dfrac{1}{1000}> \dfrac{1}{1024}

\dfrac{1}{1000}> \dfrac{1}{2^{10}}

\dfrac{1}{1000}> (\dfrac{1}{2})^{10}

If

\dfrac{N}{N_o} = \dfrac{1}{1000}

Then

\dfrac{N}{N_o} > (\dfrac{1}{2})^{10}

Consequently, it can be estimated that the minimum time elapsed is 10 half-lives.

For ^{14}\text{C}, the standard half-life time is 5730 years

Thus, the estimation of the minimum age of the charcoal is  5730 years × 10

= 57300 years

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The histogram on the left shows the number of hours students in a British Literature class read last week, rounded to the neares
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The median range of hours lies between 5 and 9.
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