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irga5000
2 months ago
11

The center of an ice rink is located at (0, 0) on a coordinate system measured in meters. Susan is skating along a path that can

be modeled by the equation y = 6x – x2 – 5. Luke starts at (10, –21) and skates along a path that can be modeled by a quadratic function with a vertex at (8, –9). If the rink is a circle with a radius of 35 meters, which statement best interprets the solution(s) of a system of equations modeling the paths of the skaters?
A. The skaters’ paths intersect once, but that point is outside the rink.

B. The skaters’ paths intersect once, and that point is inside the rink.

C. The skaters’ paths intersect twice, but only one of those points is inside the rink.

D. The skaters’ paths intersect twice, and both points are inside the rink.

Mathematics
2 answers:
Leona [12.6K]2 months ago
8 0
C
Zina [12.3K]2 months ago
3 0
Option C: The paths of the skaters intersect at two points, but only one of them falls within the rink's boundaries. Step-by-step explanation: The center of the ice rink is established at coordinates (0,0) with a radius of 35 meters. The standard equation for a circle, given the coordinates (a,b) and radius r, is (x - a)² + (y - b)² = r². Therefore, the skating area can be defined as x² + y² = 35². Susan's skating path follows the equation y = 6x - x² - 5, meanwhile, Luke maneuvers from point (10, –21) along a parabolic path centered at (8, –9). This leads us to solve for the intersection points of their paths, confirming that while they intersect twice, only one point exists within the rink's confines.
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One of the dog treats in Shelley’s shop is 8 inches long and 3.2 inches wide. She wants to make a miniature version that has pro
Inessa [12570]
Given:
Initial dog treat: 8 inches in length, 3.2 inches in width.
Miniature dog treat: 3 inches long,? wide

We will apply cross multiplication to find the proportionality:

Relating length and width.
Original treat: 8/3.2
Miniature treat: 3/x

8/3.2 = 3/x

Cross multiply:
8 * x = 3.2 * 3
8x = 9.6

Calculate x
x = 9.6/8
x = 1.2

The width of the miniature dog treat measures 1.2 inches.

To verify:
original treat: 8/3.2 = 2.5
miniature treat: 3/1.2 = 2.5
or:
8/3.2 = 3/1.2
8 * 1.2 = 3.2 * 3
9.6 = 9.6
4 0
2 months ago
Read 2 more answers
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
Zina [12379]

Response:

A 120 cm long pipe produces resonance at wavelengths of 480 cm, 160 cm, and 96 cm, but fails to resonate with any wavelengths longer than those. Consequently, this pipe is classified as:

A. closed at both ends

B. open at one end and closed on the other

C. open at both ends.

D. we cannot determine since we lack information about the sound frequency.

The correct answer is:

B. open at one end and closed at the other.

Explanation in steps:

The given data states that the pipe has a length of

= 120 cm

with wavelengthsL = 480 cm

                             

= 160 cm and \lambda_1 = 96 cm

We need to ascertain if the pipe is open, closed, or of an open-closed nature.

\lambda_2Note:\lambda_3

For a pipe open at both ends, the fundamental wavelength is 2L.

For a pipe closed at one end and open at the other, the fundamental wavelength is 4L.

  • From this information,
  • It appears that this pipe is open at one end and closed at the other.
Now let’s verify with the subsequent wavelengths.

In the case of a pipe with one open end and one closed end:[

Odd multiples of one-quarter wavelength must fit within the length L4L=4(120)=480\ cm.

⇒  

                           ⇒  

⇒

                               ⇒  

⇒                                    ⇒  ⇒

                             ⇒  

 Thus, it confirms that the pipe is open at one end and closed at the other.

6 0
2 months ago
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