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Aliun
9 days ago
8

An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes)

, one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen?
Mathematics
2 answers:
tester [11.9K]9 days ago
7 0

Final answer: 400

Detailed explanation:

Information provided: Dish count in column A = 8

Dish count in column B = 10

Dish count in column C = 5

As each dinner requires selecting one dish from each column, then

The overall number of possible dish combinations for dinner is:-

8\times10\times5=400

Thus, total family dinners = 400

Zina [11.9K]9 days ago
7 0
The result is calculated as 10 multiplied by 8 multiplied by 5, which equals 400.
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