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VikaD
1 month ago
5

The Wild Dogs and the Rattlers also have membership programs. The Wild Dogs' initial fee is $20 and single-game tickets are $1.5

0. The Rattlers' initial fee is $14 and single-game tickets are $2.25. The system of equations for this scenario are y = 1.5x + 20 and y = 2.25x + 14, where x=tickets purchased and y=total cost.
What is the best window range of x-values to find the solution?


What is the best window range of y-values to find the solution?


What is the solution?
Mathematics
2 answers:
zzz [12.3K]1 month ago
6 0
The equation is represented by y=20+1.5x.
tester [12.3K]1 month ago
6 0
The initial answer is: ✔ x-min = 0, x-max = 20 ✔ y-min = 20, y-max = 40 ✔ 8 games will cost $32.
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The annual net income of a company for the period 2007–2011 could be approximated by P(t) = 1.6t2 − 11t + 44 billion dollars (2
babunello [11817]

Answer:

P'(t) = 3.2 t -11

To identify the critical point, we set the derivative equal to zero, resulting in:

3.2 t-11= 0

t = \frac{11}{3.2}= 3.4375

Calculating the second derivative yields:

P''(t) = 3.2 >0

This indicates that t = 3.4375 marks the minimum value for the function. Substituting this back into the original function gives us:

P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094

Thus, the minimum annual income is found at t = 3.43 (between the years 2008 and 2009), with a value of 25.094

Step-by-step explanation:

In this scenario, we have the function:

P(t) = 1.6 t^2 -11t +44

Where P represents the annual net income from 2007-2011, and 2 \leq t \leq 7

t is the number of years since early 2005

To discover the lowest income, we utilize the derivative given by:

P'(t) = 3.2 t -11

Setting this derivative to zero allows us to find the critical point, leading to:

3.2 t-11= 0

t = \frac{11}{3.2}= 3.4375

Calculating the second derivative reveals:

P''(t) = 3.2 >0

Therefore, we conclude that t = 3.4375 is the minimum value, substituting into the original function results in:

P(3.4375) = 1.6(3.4375)^2 - (11*3.4375) +44 = 25.094

Thus, the minimum annual income occurs at t = 3.43 (between 2008 and 2009) with the value being 25.094

5 0
1 month ago
The sum of the first 1 million primes is N. Without knowing N's value, one can determine that the ones'digit of N cannot be
babunello [11817]
All prime numbers are odd with the exception of two. Hence, if we consider the sum of the first million primes, it consists of one even number combined with 999,999 odd numbers. Since the product of an odd number multiplied by another odd number results in an odd number, we conclude that the sum must be an odd number, being even + odd = odd.

It's clear that an odd number ends with an odd digit, so the only digit that can be eliminated is b (an even digit).
3 0
2 months ago
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