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nlexa
14 days ago
10

Conor buys 75 tokens for games at the arcade. The price to play each game is 3 tokens. If Conor has already played x games, whic

h expression is equivalent to the number of tokens that remain?
A. 3x – 75
B. 3(25 – x)
C. 3(25 + x)
D. 75 + 3x
Mathematics
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Write three numbers for which you would use the hundreds place to compare to 35,712​
Leona [12618]

Answer:

  • 35,694
  • 35,981
  • 35,102

Step-by-step explanation:

If you compare numbers based on the hundreds digit, the digits to the left (thousands and ten-thousands) remain the same, while the hundreds digit differs.

This applies for any five-digit numbers structured like:

(3)(5)(not 7)(any digit)(any digit).

Digits to the right of the decimal point, as well as those in the tens and ones places, don't impact this comparison.

5 0
3 months ago
#6) Beth saved a total of $30 per month for her first car. Beth saved
PIT_PIT [12445]
1) The domain is represented in interval notation as [0, 20]. 2) The range is denoted as [100, 700]. Given that Beth saves $30 per month for 20 months and started with an account of $100, we express the total amount saved as Y = $100 + $30 × X, allowing us to accurately define both the domain and range.
6 0
1 month ago
A home’s value increases at an average rate of 5.5% each year. The current value is $120,000. What function can be used to find
Svet_ta [12734]

Answer:

f(x)=120000 \times (1.055)^{x}

Step-by-step explanation:

The present value of the house is $120,000 and the interest rate is 5.5%, or 0.055.

We will utilize the following equation:

f(x)=P \times (1+r)^{x}

where P represents the present value, r symbolizes the interest rate, and x refers to the number of years.

By inputting the values into the above equation, we can obtain:

f(x)=120000 \times (1+0.055)^{x}

f ( x ) = 120000 \times ( 1.055 ) ^ { x }

8 0
1 month ago
Read 2 more answers
In a sample of 88 adults selected randomly from one town, it is found that 6 of them have been exposed to a particular strain of
tester [12383]

Response with clarification:

Let p denote the proportion of adults in the town who have encountered this flu strain.

According to the provided information

H_0:p=0.08\\\\ H_a: p\neq0.08

∵ H_a this is a two-tailed test.

Test statistic:

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

, where p= denotes the population proportion

{\hat{p} = signifies the sample proportion

n= represents the sample size

Setting n= 6 and {\hat{p}=\dfrac{6}{88}\approx0.068 and p=0.08

z=\dfrac{0.068-0.08}{\sqrt{\dfrac{0.08(1-0.08)}{88}}}

z=\dfrac{-0.012}{0.0289199522192}\approx-0.415

P-value for the two-tailed test:[2P(Z>|z|)

=2P(Z>|-0.415|)

=2P(Z>0.415) = 2[1-P(Z≤0.415)] [∵ P(Z>z)=1-P(Z≤z)]

=2(1-0.6609) [from the z-table]

=0.6782

Decision: Because the p-value(0.6782) exceeds the significance level of 0.01, we do not reject the null hypothesis.

This leads us to conclude that there is insufficient evidence to back the assertion that the percentage of all adults in this town exposed to this flu strain deviates from the national average of 8%.

8 0
1 month ago
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