Greetings:
<span>x² + y² + 8x + 22y + 37 = 0
(x² +8x) +(y² +22y) +37 = 0
</span>(x² +8x+4²)-4² +(y² +22y+11²) -11²+37 = 0
(x+4)² +(y+11)²-16-121+37 =0
(x+4)² +(y+11)² =10²...(<span>standard form )
</span><span>The circle's center is located at (-4, -11) and has a radius of 10</span>
Answer:
The measurement of angle HBC is m∠HBC=61°
Step-by-step explanation:
The given problem states that
The line BH divides angle EBC into two equal parts,
consult the attached diagram for clarity
thus
m∠EBC=m∠EBH+m∠HBC
where m∠EBH=m∠HBC
therefore
m∠EBC=2(m∠EBH)
Insert the provided values to solve for a

Determine the value of angle EBH
m∠EBH=(4(4)+45)=61°
Keep in mind that
m∠EBH=m∠HBC
therefore
The measurement of angle HBC is m∠HBC=61°
Percentage change in price = 13.80%.
Perimeter (P)= 2Length (L) +2Width (W)
P=2L + 2W
P=(2y)+(3y-5)
P=5y-5
A. 5y-5