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13 days ago

50 pts!!!! Luciana's laptop has 3,000 pictures. The size of the pictures is skewed to the right, with a mean of 3.7MB and a stan

dard deviation of 0.78MB. Part A: Can you accurately calculate the probability that the mean picture size is more than 3.8MB for an SRS of 20 pictures? Explain. (4 points) Part B: If you take a random sample of 60 pictures instead of 20, explain how the Central Limit Theorem allows you to find the probability that the mean picture size is more than 3.8MB. Calculate this probability and show your work. (6 points)

Mathematics

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5 Adoncia makes a scale drawing of the front of

zzz [12365]

Answer:

Due to the drawing measuring 200 ft., which translates to 13.33 in. with a scale of 15 ft to 1 in., and given that the sheet of paper is 11 in. long, Adoncia's depiction will not fit onto the paper.

Step-by-step explanation:

The provided details include;

The scale is 15 ft = 1 in.

The actual monument's dimensions;

Height = 80 ft.

Length = 200 ft.

Hence, we can establish;

The necessary paper height = 80/15 = 16/3 = 5.33 in.

The necessary paper length = 200/15 = 40/3 = 13.33 in.

As the paper size provided is 11 in., which is standard at 8.5 in. by 11 in.,

The drawing length of 13.33 in. exceeds the available paper length of 11 in.

Thus, Adoncia's drawing will not fit on the paper.

4 0

2 months ago

What is true about the solution of StartFraction x squared Over 2 x minus 6 EndFraction = StartFraction 9 Over 6 x minus 18 EndF

PIT_PIT [12445]

Answer:

$x=\pm\sqrt{3}$ and these represent genuine solutions.

Step-by-step explanation:

We have

$\frac{x^2}{2x-6}=\frac{9}{6x-18}$

Factor both sides' denominators.

$\frac{x^2}{2(x-3)}=\frac{9}{6(x-3)}$

Simplify.

$\frac{x^2}{2}=\frac{9}{6}$

$x^2=\frac{18}{6}$

$x=\pm\sqrt{3}$

Verify

1) For $x=\sqrt{3}$

$\frac{\sqrt{3}^2}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}$

$\frac{3}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}$

$18=18$ ---> is valid.

Thus,

$x=\sqrt{3}$ -----> is a legitimate solution.

2) For $x=-\sqrt{3}$

$\frac{-\sqrt{3}^2}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}$

$\frac{3}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}$

$18=18$ ---> is valid.

Therefore,

$x=-\sqrt{3}$ -----> is a legitimate solution.

Thus,

3 0

2 months ago

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The equation that represents the canned goods order is 24x + 64y = 384, where x = number of minutes spent producing fruit cans,

zzz [12365]

We must determine the value of x

4 0

2 months ago

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Matthew bought flowers for his mom. he bought 12 flowers that were a combination of roses and lilies. the roses cost $1.75 each

Inessa [12570]

To tackle this issue, follow the outlined procedure: 1. Designate variables: let’s say $x$ is the count of roses and $y$ represents the number of lilies. 2. Construct a system of equations based on the provided details in the problem statement above. 3. Utilize substitution method: first, resolve for $x$ in the second equation, substitute it into the first equation, then solve for $y$ . 4. Next, substitute $y=3$ back into the second equation. Consequently, the answer will be: $9$ roses and $3$ lilies.

5 0

1 month ago

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