a) Approximately 40° for depression and 5° for elevation; b) it relates to the height of the observer; c) none. Step-by-step explanation: (a) Angles of depression and elevation: The angle of depression is roughly 40°, while the angle of elevation is around 5°. (b) The angles depend on the observer's height. A taller individual will have a smaller angle of elevation paired with a larger angle of depression. (c) None of the angles can reach or exceed 99°, since they are components of a right triangle. If one angle is a right angle, both of the others must be lesser than 90°.
Angles that are opposite to each other when two lines cross are equal, therefore angle 1 is equal to angle 4. This also implies that angle 1 = angle 5. When a line crosses two parallel lines, the angles corresponding to each other are equal. So, if r and s are parallel, the angles that are formed when line l intersects line r are equal to those when l intersects line s. Thus, we have angle 1 = angle 5, angle 2 = angle 6, and so on. Hence, since angle 1 is equal to angle 5, we deduce that lines r and s are parallel.
To formulate a system of equations for Naomi and Hudson, who work at a dry cleaners where Naomi can iron 35 shirts per hour and Hudson can manage 20 shirts per hour, we know that together they worked 13 hours and completed a total of 395 shirts. Naomi, during her 13 hours, could potentially iron 455 shirts (13 x 35), meaning each hour Hudson worked lessens that number by 15 shirts. The difference of 60 shirts (455 - 395) indicates that Hudson worked for 3 hours and Naomi, therefore, for 10 hours. The resulting equation reflects this relationship: 35Y + 20X = 395.
Answer:
The top surface area of the washer equals 160.14 square millimeters.
Step-by-step Explanation:
The washer's top surface forms an annulus, characterized by an outer radius of 10 mm and an inner radius of 7 mm (obtained since the hole's diameter is 14 mm and the radius is half the diameter).
Recall the formula for the area of an annulus:
where R is the outer radius and r the inner radius.
Substituting the given values:
Thus, the calculation yields:
