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dolphi86
1 month ago
13

El área de una propiedad en metros cuadrados, mide 704/5. Se construye una casa que ocupa 5/6 del área total. La mitad del área

restante se utiliza para construir una terraza, cuanta área falta por construir?
Mathematics
1 answer:
tester [12.3K]1 month ago
8 0

Answer:

The remaining area available for construction is \frac{704}{60}\ m^{2}

Step-by-step analysis:

The inquiry in English reads

The total area of a property, measured in square meters, amounts to 704/5. A house is constructed occupying 5/6 of this area. Half of the leftover space is utilized for a terrace; thus, how much area remains for additional construction?

We know that

The total area is represented by the fraction 6/6

A house accounts for 5/6 of the entire area

Thus, the remaining area is (6/6)-(5/6)=1/6 of the overall area

If half of this leftover area is designated for a terrace

then

the terrace occupies (1/6)/2=1/12 of the total area

consequently,

The area remaining for construction is 1/12 of the total area

therefore

(\frac{1}{12})\frac{704}{5} =\frac{704}{60}\ m^{2}

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Answer:

Step-by-step explanation:

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Case 2:

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Step-by-step explanation:

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1 month ago
pat made a total of 48 pottery plates and cups if she made twice as many plates as cups how many plates did she make?
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2 months ago
In right triangle qrs, angle r is a right angle. The altitude rt is drawn to hypotenuse qs. If qr is 20 and qs is 25 then find t
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Answer:

qt's length = 16

Step-by-step explanation:

The problem states that qrs is a right triangle,

where qr = 20

          sr =?

          qs = 25

          qt =?

1)

Calculate sr

hypotenuse² = base² + height²

sq² = sr² + rq²

25² - 20² = sr²

sr = √(25² - 20²)

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2)

When altitude rt is dropped to hypotenuse qs, it creates

two right triangles: rtq and rts.

Δrtq

height = rt

base= tq = 25 - x

hypotenuse = qt = 20

Δrts

height = rt

base= ts = x

hypotenuse = sr = 15

Both triangles share the same height, which is rt

Using the Pythagorean theorem:

      Δ rtq                                           Δ rts

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400 - 625 - x² + 50x = 225 - x²

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Base of Δ rtq = tq = 25 - x

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                         tq = 16  

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1 month ago
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