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SashulF
2 months ago
12

A high school student took two college entrance exams, scoring 1070 on the SAT and 25 on the ACT. Suppose that SAT scores have a

mean of 950 and a standard deviation of 155 while the ACT scores have a mean of 22 and a standard deviation of 4. Assuming the performance on both tests follows a normal distribution, determine which test the student did better on.
Mathematics
1 answer:
Zina [12.3K]2 months ago
8 0

Answer:

His superior z-score indicates better performance on the SAT.

Step-by-step explanation:

In the case of a normal distribution, we utilize the z-score formula.

For a dataset with a mean of \mu and a standard deviation of \sigma, the z-score of a given value X is defined by:

Z = \frac{X - \mu}{\sigma}

The z-score illustrates how many standard deviations away the given measurement is from the average. Once we calculate the z-score, we refer to the z-score table to locate the p-value corresponding to this z-score. This p-value indicates the likelihood that the measure is less than X, effectively representing the percentile for X. By subtracting the p-value from 1, we derive the probability that the measurement exceeds X.

Identify which exam the student performed better on.

He excelled in the exam where he had a higher z-score.

SAT:

With a score of 1070, thus X = 1070

SAT averages are 950 with a standard deviation of 155. Therefore, \mu = 950, \sigma = 155.

Z = \frac{X - \mu}{\sigma}

Z = \frac{1070 - 950}{155}

Z = 0.77

ACT:

With a score of 25, thus X = 25

ACT averages are 22 with a standard deviation of 4. This implies that \mu = 22, \sigma = 4

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4}

Z = 0.75

His greater z-score shows that he performed better on the SAT.

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