We have the equations d=55t and d=20g. The left sides match, as do the right sides. First, we derive the equation: 55t=20g. Then, we can deduce that g=(55/20)t. If t=6 hours, then g=(55/20) *6 = 165/10=16.5 gallons. The distance can be calculated as d= 55t= 55*6=330 miles, which is also equal to d=20g=20*16.5=330 miles.
It is stated that a straight rod has one endpoint at the origin (0,0) and the opposite endpoint at (L,0), with a linear density defined by
, where a is a constant and x is the x coordinate.
Thus, the infinitesimal mass is expressed as:

The total mass can be calculated by integrating the above expression as follows:

Consequently, ![m=a\int\limits^L_0 {x^2} \, dx=a[\frac{x^3}{3}]_{0}^{L}=\frac{a}{3}[L^3-0]= \frac{aL^3}{3}](https://tex.z-dn.net/?f=m%3Da%5Cint%5Climits%5EL_0%20%7Bx%5E2%7D%20%5C%2C%20dx%3Da%5B%5Cfrac%7Bx%5E3%7D%7B3%7D%5D_%7B0%7D%5E%7BL%7D%3D%5Cfrac%7Ba%7D%7B3%7D%5BL%5E3-0%5D%3D%20%5Cfrac%7BaL%5E3%7D%7B3%7D)
Now, we can calculate the center of mass,
of the rod as:


Now, it follows that
x_{cm}=\frac{1}{\frac{aL^3}{3}}\int_{0}^{L}ax^3dx=\frac{3}{aL^3}\times [\frac{ax^4}{4}]_{0}^{L}
Therefore, the center of mass,
is located at:
![\frac{3}{aL^3}\times [\frac{ax^4}{4}]_{0}^{L}=\frac{3}{aL^3}\times \frac{aL^4}{4}=\frac{3}{4}L](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7BaL%5E3%7D%5Ctimes%20%5B%5Cfrac%7Bax%5E4%7D%7B4%7D%5D_%7B0%7D%5E%7BL%7D%3D%5Cfrac%7B3%7D%7BaL%5E3%7D%5Ctimes%20%5Cfrac%7BaL%5E4%7D%7B4%7D%3D%5Cfrac%7B3%7D%7B4%7DL)
Answer:
Noah is the only one correct.
Step-by-step explanation:
The volume of the cube is calculated as 10^3 = 1000 units.
The total volume combining the cube and the prism is 1000 + 20 =
1020 cubic units.
Answer:
cuando hables de raviolis de queso, dile a Martha que vaya al supermercado a comprar raviolis Chef Boyardee.
X - 3 = 2x - 13
+x +x
-3 = 3x - 13
+13 +13
10 = 3x
10/3 3/3
3.3 = x