Identify a transformation of the function ƒ(x) = x by observing the equation of the function g(x) = m ⋅ x, with m > 1

The translation rule can be expressed as T -3,1(x,y). The translation can also be indicated as (x,y)➡️(x-3,y+1).

Answer:

The equation 0 = 3x² + 17x - 160 might be useful in determining the length.

Step-by-step explanation:

The area of the vegetable garden is specified as 170 ft².

Now, regarding the provided equations;

1) For 0 = 3x² + 2x + 180, applying the quadratic formula results in:

x = [-2 ± √(3² - 4(3 × 180)]/(2 × 3)

x = [-2 ± √(-2151)]/6

The square root value is negative, indicating no real solution for x.

Thus, this equation does not help find the length.

2) For the equation 0 = 3x² + 10x + 180, employing the quadratic formula, the square root value is also negative, hence there's no natural root for x. This means this equation can't be used to determine the length.

3) For 0 = 3x² + 17x - 160, the roots when using the quadratic formula yield -10.67 or 5. The value 5 is viable since it is a whole number. Considering the area is also a whole number, this equation can be applied to ascertain the length.

4) For 0 = 3x² - 160, simplifying gives;

3x² = 160

x² = 160/3

x = ±√(160/3)

x = ±7.303

Since the area is a whole number but this length isn't, this equation may not accurately determine the length.

(a) 4 <span>(b) y = sqrt(9 - (9/16)x^2) </span>The most accurate assumption for the equation based on the general format for an ellipse is: [[TAG_3]]x^2/16 + y^2/9 = 1 [[TAG_4]](a). An ellipse is symmetrical along both its major and minor axes. Thus, if you can calculate the area of the ellipse in one quadrant, multiplying that area by 4 will yield the total area of the ellipse, confirming the factor of 4 is accurate. [[TAG_5]] (b). The standard equation for an ellipse doesn't adequately represent a general function as it results in two y values for each x value. However, if we constrain ourselves to the positive square root, that issue can be resolved easily. Here’s how: [[TAG_6]] x^2/16 + y^2/9 = 1 [[TAG_7]] x^2/16 + y^2/9 - 1 = 0 [[TAG_8]] x^2/16 - 1 = - y^2/9 [[TAG_9]] -(9/16)x^2 + 9 = y^2 [[TAG_10]] 9 - (9/16)x^2 = y^2 [[TAG_11]] sqrt(9 - (9/16)x^2) = y [[TAG_12]] y = sqrt(9 - (9/16)x^2)

Answer:

4:5

Step-by-step explanation:

Start with the equation:

2(3/4m)=D+1/4m

Then, simplify to solve:

5/4m=D