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mixas84
2 months ago
10

One sphere has a radius of 5.10 cm; another has a radius of 5.00cm. What is the difference in volume (in cubic centimeters) betw

een the two spheres? The volume of the sphere is (4/3)*pi*r^3, where pi=3.1416. How do you know?
Mathematics
2 answers:
AnnZ [12.3K]2 months ago
8 0

According to the formula for the volume of a sphere, it is represented as:

V = (\frac{4}{3}) * \pi * r ^ 3

In this case,

r indicates the radius of the sphere.

Thus, to determine the difference in volumes of the two spheres, we calculate:

V1 - V2 = (\frac{4}{3}) * \pi * r1 ^ 3 - (\frac{4}{3}) * \pi * r2 ^ 3

By rearranging, we derive:

V1 - V2 = (\frac{4}{3}) * \pi * (r1 ^ 3 - r2 ^ 3)

By entering the values, we find:

V1 - V2 = (\frac{4}{3}) * 3.1416 * (5.10 ^ 3 - 5 ^ 3)\\V1 - V2 = 32.05 cm ^ 3

The outcome is:

The resulting difference in volume (in cubic centimeters) for the two spheres amounts to:

V1 - V2 = 32.05 cm ^ 3

lawyer [12.5K]2 months ago
5 0
\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\qquad 
\begin{cases}
r=radius\\
-----\\
r_1=5.10\\
r_2=5
\end{cases}\implies \cfrac{V_1}{V_2}\implies \cfrac{\frac{4\pi \cdot 5.10^3}{3}}{\frac{4\pi \cdot 5^3}{3}}
\\\\\\
\cfrac{\underline{4\pi }\cdot 5.10^3}{\underline{3}}\cdot \cfrac{\underline{3}}{\underline{4\pi }\cdot 5^3}\implies \cfrac{5.10^3}{5^3}\implies \cfrac{132.651}{125}
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