Detailed explanation:
Work completed by Gardner each hour = 1 / 5
Combined work done by Gardner and assistant each hour = 1 / 4
Work done by the helper per hour
= 1 / 4 - 1 / 5
= 1 / 20
Time required for helper to finish the job:
= 20 hours
In detail: Based on the central limit theorem, the distribution appears normal due to the large sample size. The confidence interval is presented in the format: (Sample mean - margin of error, sample mean + margin of error). The sample mean, denoted as x, serves as the point estimate for the population mean. The confidence interval is computed as: mean ± z × σ/√n, where σ represents the population standard deviation. The formula transforms into confidence interval = x ± z × σ/√n, with specific values: x = $75, σ = $24. To find the z score, we subtract the confidence level from 100% which gives α as 1 - 0.96 = 0.04; halving this results in α/2 = 0.02, signifying the tail areas. To ensure we account for the center area, we have 1 - 0.02 = 0.98, corresponding to a z score of 2.05 for the 96% confidence level. The confidence interval becomes 75 ± 2.05 × 24/√64 = 75 ± 2.05 × 3 = 75 ± 6.15. The lower limit is 75 - 6.15 = 68.85, while the upper limit stands at 75 + 6.15 = 81.15. For n = 400, with x = $75 and σ = $24, the z score remains 2.05, resulting in the confidence interval calculated as 75 ± 2.05 × 24/√400 = 75 ± 2.05 × 1.2 = 75 ± 2.46. Subsequently, the lower bound becomes 75 - 2.46 = 72.54, and the upper limit adds up to 75 + 2.46 = 77.46. Lastly, when n = 400, x = $200, and σ = $80, the z score tied to a 94% confidence level is 1.88. Thus, the confidence interval is expressed as 200 ± 1.88 × 80/√400 = 200 ± 1.88 × 4 = 200 ± 7.52, giving us a margin of error of 7.52.
Response:
- Refer to the attached graph
Clarification:
To analyze log (−5.6x + 1.3) = −1 − x visually, graph these equations on the same coordinate system:
- Equation 1: y = log (5.6x + 1.3)
The first equation can be graphed using these characteristics of logarithmic functions:
- Domain: values must be positive ⇒ -5.6x + 1.3 > 0 ⇒ x < 13/56 (≈ 0.23)
- Range: all real values (- ∞, ∞)
log ( -5.6x + 1.3) = 0 ⇒ -5.6x + 1.3 = 1 ⇒ x = 0.3/5.6 ≈ 0.054
x = 0 ⇒ log (0 + 1.3) = log (1.3) ≈ 0.11
- Choose additional values to create a table:
x log (-5.6x + 1.3)
-1 0.8
-2 1.1
-3 1.3
- This graph is shown in the attached image: it's represented by the red curve.
Graphing the second equation is simpler as it forms a straight line: y = - 1 - x
- slope, m = - 1 (the coefficient of x)
- y-intercept, b = - 1 (the constant term)
- x-intercept: y = 0 = - 1 - x ⇒ x = - 1
- This graph is indicated by the blue line in the image.
The resolution to the equations corresponds to the points where the two graphs intersect. The graphing method thus allows you to determine the x coordinates of these intersection points. Ordered from smallest to largest, rounded to the nearest tenth, we have:
Answer:
(a) What will his age be after 5 years?
"5 + y" years old
(b) What was his age 6 years ago?
"y - 6" years old
(c) If his grandfather’s age is five times his, how old is his grandfather?
"5y" years old
(d) His father is 6 years older than three times his age. How old is his father?
"6 + 3y" years old
Note: Disregard the quotation marks, ""
Answer:
________{0.50 if x < 3
________{1.00 if 3 ≤ x < 6
f(x) = ____{1.50 if 6 ≤ x < 9
________{2.00 if 9 ≤ x < 12
Step-by-step explanation:
Based on the details provided:
Employees with less than 3 years receive an increase of $0.50 hourly
Employees with at least 3 years but under 6 years receive $1.00 increase hourly
Employees with a minimum of 6 years and less than 9 get $1.50 increase hourly
Employees with at least 9 years but below 12 years receive $2.00 increase hourly
This information can be expressed as a piecewise function:
________{0.50 if x < 3
________{1.00 if 3 ≤ x < 6
f(x) = ____{1.50 if 6 ≤ x < 9
________{2.00 if 9 ≤ x < 12
The conditions are outlined in the piecewise function above with x indicating the number of years employed.
