a bullet of mass m is fired into a block of mass m that is at rest. the block, with the bullet embedded, slides distance d acros

The relatively high resistivity of dry skin, about 1×106Ω⋅m, can safely limit the flow of current into deeper tissues of the bod

ValentinkaMS [3465]

Answer:

The resistance of the skin is 98 kΩ

Explanation:

Given:

Resistivity $\rho = 1 \times 10^{6}$ Ωm

Thickness $t = 1.5 \times 10^{-3}$ m

Resistivity of the skin:

$R = \frac{\rho t}{A}$

With assumed radius for the worker's palm,

$r = 7 \times 10^{-2}$ m

Area of the worker's palm,

$A = \pi r^{2}$

$A = 3.14 \times 49 \times 10^{-4}$

$A = 1.53 \times 10^{-2}$ $m^{2}$

Thus the resistance of palm is,

$R = \frac{10^{6} \times 1.5 \times 10^{-3} }{1.53 \times 10^{-2} }$

$R = 98 \times 10^{3}$ Ω

Consequently, the resistance of the skin is 98 kΩ

3 0

1 month ago

The acceleration due to gravity for any object, including 1 washer on the string, is always assumed to be m/s2. The mass of 3 wa

Keith_Richards [3271]

Answer:

The force will rise in direct relation to the mass of the objects

Explanation:

The gravitational acceleration remains constant. It is measured in meters per second squared or m/s². The average value is 9.81 m/s², calculated from observations made on varying surfaces. In reality, the acceleration can vary based on the geographical shape of the Earth relative to the earth's magnetic field and gravitational force.

For instance, if a single washer weighs 20 kg, with the gravity at 9.81 m/s², the weight would be:

F = ma

= $20 * 9.81\\= 196.2 N$