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iren
8 days ago
13

A cleaver physics professor wants to create a situation where a block starts from rest at the top of a 31.0° inclined plane and

encounters a spring at the bottom of the incline. The spring has a constant 3.4 kN/m and the block's mass is 33.0 kg. How far does the block travel before hitting the spring, if the spring was compressed 37 cm in it's initial collision?
Physics
1 answer:
Softa [3K]8 days ago
8 0
Let L be the length of the inclined plane. The work done by gravity on the block is calculated as the product of force and distance traveled, which amounts to mg sinθ x L, where m stands for the mass of the block and θ denotes the angle of inclination. This translates into the potential energy of the compressed spring represented by 1/2 k x² = mgL sin31, with k as the spring constant. Compression x measures 0.37. Solving this gives: 0.5 x 3400 x 0.37² = 33 x 9.8 x sin31 L yields L = 1.4 m, indicating the incline measures 1.4 meters.
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