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Anton
3 months ago
13

Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th

rough sides D B and C B. Lines D C and R S are parallel. width= Which statements are correct? Select three options. △BCD is similar to △BSR. StartFraction B R Over R D EndFraction = StartFraction B S Over S C EndFraction If the ratio of BR to BD is Two-thirds, then it is possible that BS = 6 and BC = 3. (BR)(SC) = (RD)(BS) StartFraction B R Over R S EndFraction = StartFraction B S Over S C EndFraction

Mathematics
1 answer:
Zina [12.3K]3 months ago
7 0

Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).

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Respuesta:

0.0143 = 1.43% de probabilidad de que los primeros 4 dígitos del código sean números pares.

Explicación paso a paso:

Arreglos de elementos n:

El número de arreglos posibles de n elementos se determina por:

A_{n} = n!

Probabilidad:

La probabilidad se calcula dividiendo el número de resultados deseados por el número total de resultados.

En esta pregunta:

Resultados deseados:

Los primeros cuatro dígitos son pares (2, 4, 6 y 8 son pares, así que se consideran 4 elementos).

Los últimos cuatro dígitos son impares (1, 3, 5 y 7 son impares, por lo que los últimos cuatro elementos son también arreglos de 4 elementos). Entonces

D = 4!*4! = 24*24 = 576

Resultados totales:

Arreglos de 8 dígitos. Así que

T = A_{8} = 8! = 40320

Probabilidad:

p = \frac{D}{T} = \frac{576}{40320} = 0.0143

0.0143 = 1.43% de probabilidad de que los primeros 4 dígitos del código sean números pares.

3 0
2 months ago
Witch of the functions below could possibly have created this graph? A.f(x)-x^5+2x^4-3x B.f(x)=-1/3x^4+7x^2+15 C.f(x)=1.9x^8+15x
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B. f(x)=-1/3x^4+7x^2+15. You can visualize the function using a graphing tool for better understanding.
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2 months ago
The current global human population is about 6.1 billion and is growing at an annual rate of 1.35 percent. If world population w
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Answer:

Step-by-step explanation:

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t symbolizes the number of years.

P is the initial population count.

r signifies the growth rate.

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r = 1.35% = 1.35/100 = 0.0135

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Hence,

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3 months ago
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