Given:
1 pack = 5 pencils and cardboard.
1 pack should weigh between 60 grams and 95 grams
60g < x < 95g; where x signifies 1 pack.
Cardboard: 15 grams.
95g - 15g = 80g represents the maximum total weight of 5 pencils.
80g / 5 = 16g is the maximum weight for a single pencil.
60g - 15g = 45g is the minimum total weight of 5 pencils.
45g / 5 = 9g is the minimum weight for a single pencil.
9 < x < 16; where x represents a single pencil in the pack.
We consider all workers as either full-time or part-time.
36 = 24 + 12
If there are 24 or fewer full-time workers, there must be at least 12 part-time workers. (This conclusion is based on the understanding of sums.)
You can formulate the inequality in two steps. First, present and resolve an equation for full-time workers in relation to part-time workers. Then, apply the specified limit on full-time workers. This results in an inequality that can be solved for part-time workers.
Let f and p represent full-time and part-time positions, respectively.
f + p = 36... given
f = 36 - p... subtract p to express f in terms of p.
f ≤ 24......... given
(36 - p) ≤ 24.... substitute for f. This gives your inequality in terms of p.
36 - 24 ≤ p.... rearranging gives p ≥ 12........ this is the solution to the inequality
Answer:
Steven is mistaken.
Step-by-step explanation:
Steven has
- 9 unique shirts
- 5 unique hats
- 4 unique scarves.
He selects only two out of the three types of clothing. The combinations can be calculated as
-
options to select a shirt and a hat;
options to select a hat and a scarf;
options to select a shirt and a scarf.
In total, there are

different methods to choose just two out of the three clothing items.
As a result,
Steven is not correct.