Since the ball achieves a peak height of 18 meters at 1 second, it will begin descending thereafter. Therefore, we anticipate that the height will drop below 18 m after 1.5 sec.
f(x) = –10x2 + 20x + 8
f(x) = –10(1.5^2) + 20(1.5) + 8
f(x) = 15.5 m
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V = x³ - 6x²y + 12xy² - 8y³
V = (x - 2y)³
= (x - 2y)(x - 2y)(x - 2y) ( start by expanding the first pair of factors )
= (x² - 4xy + 4y²)(x - 2y) ( multiply the terms from the first group with those in the second )
= x³ - 4x²y + 4xy² - 2x²y + 8xy² - 8y³ ( combine similar terms )
= x³ - 6x²y + 12xy² - 8y³
1 product = $65.00
20 products = 65 x 20 = $1300
Sales Tax is 3.5% of $1300 = 0.035 x $1300 = $45.50
Grand total = $1300 + $45.50 = $1345.50
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Response: $1345.50
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Let’s define x as the amount invested by Sam in the first year.
Here are the corresponding expressions derived from the provided descriptions for Sam's investments.
For Sam:
2nd year: investment = 5x/2 - 2000
3rd year: investment = x/5 + 1000
The total Sam invested is:
x + (5x/2 - 2000) + (x/5 + 1000)
Next, we can form the expressions for Sally’s investments.
For Sally
1st year: investment = 3x/2 - 1000
2nd year: investment = 2x - 1500
3rd year: investment = x/4 + 1400
Thus, Sally's total investment is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Setting both totals equal gives us:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Solving for x,
x = 2000
For Sally's investment for the third year:
investment = x/4 + 1400 = (2000/4 + 1400) = 1900
RESULTS:
Sam's first year = $2000
Sally's third year = $1900
