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goldenfox
16 days ago
6

Two thirds a number plus 4 is 7

Mathematics
2 answers:
PIT_PIT [3.9K]16 days ago
5 0
Assign the variable "x" to represent the unknown number.

The equation based on the statement is:
_____________________________________
(⅔)x + 4 = 7.
_____________________________________
To solve for "x":

First, subtract "4" from both sides:

(⅔)x + 4 − 4 = 7 − 4;

which simplifies to:

(⅔)x = 3;

Next, multiply both sides by "3" to eliminate the fraction's denominator:

3 × (⅔)x = 3 × 3;

resulting in: 2x = 9;

Finally, divide both sides by "2" to isolate "x":
__________________________________________________
     (2x) / 2 = 9 / 2

x = 9/2 = "4 ½" or "4.5".
_______________________________________




zzz [4K]16 days ago
4 0
Let's denote the unknown number as 'n'.
The plus sign represents addition.
The word 'is' corresponds to the equals sign.

So, the expression can be written as: \frac{2}{3} n + 4 = 7
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Answer:

Detailed steps:

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9 days ago
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Answer:

We conclude that less than or equal to 50% of the student body supports him significantly.

Step-by-step explanation:

Mike, while campaigning for the student government presidency, is keen to determine if more than 50% of the student body supports him.

A random sample of 100 students was surveyed, with 55 expressing support for Mike.

Let p = the proportion of students backing Mike.

Thus, Null Hypothesis, H_0: p \leq 50% {indicating that the proportion of supporters among the student body is significantly less than or equal to 50%}

Alternate Hypothesis, H_A: p > 50% {indicating that the proportion of supporters among the student body is significantly more than 50%}

The test statistics to be utilized here One-sample z proportion statistics;

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where, \hat p = the sampled proportion in favor of Mike = \frac{55}{100} = 0.55

n = number of sampled students = 100

Therefore, test statistics = \frac{0.55-0.50}{\sqrt{\frac{0.55(1-0.55)}{100} } }

= 1.01

The z test statistic is 1.01.

At a significance level of 0.05, the z table provides a critical value of 1.645 for a right-tailed test.

Given that our test statistic falls below the critical value of z (1.01 < 1.645), we lack sufficient evidence to reject the null hypothesis as it remains outside the rejection region, leading to failure to reject our null hypothesis.

As a result, we conclude that less than or equal to 50% of the student body is in favor of him or the proportion supporting Mike is not significantly greater than 50%.

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Answer:

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