Answer:
Vertex: (1, -4)
intercept: (-3, 0)
Step-by-step explanation:
Let's be honest, you're not here for a detailed breakdown; you simply want the answer.
HOWEVER... the vertex corresponds to the Y-axis while the intercept aligns with the X-axis.
Answer:
Expiration Date: 1/17/2017
Expiration Time: 4:00am
Preparation Date: 12/3/2016
Preparation Time: 4:00am
Initial Usage Date: 12/7/2016
Detailed Breakdown:
An illustrative depiction of the question has been provided in an image format for clarity.
From the information given, it is noted that her store order arrived on 12/3/2016 at 4am, confirming that both the prep date and time are 12/3/2016 and 4am respectively. The product has a printed expiration date of 1/17/2017, logically indicating that its expiration time is also 4am, in line with the prep time; adding 24 hours leads us back to the same time on the expiration date. Furthermore, we were informed that she utilized the product on 12/7/2016, which marks the initial use date. Based on this information, we can summarize as follows:
Expiration Date: 1/17/2017
Expiration Time: 4:00am
Preparation Date: 12/3/2016
Preparation Time: 4:00am
Initial Usage Date: 12/7/2016
20*117.98 + 20*124.32 = $4846.00
<span>$4846.00*1.02 = $4942.92 </span>
<span>40*128.48 = $5139.20 </span>
<span>0.02*5139.20 = $102.78 </span>
<span>$5139.20 - $102.78 = $5036.42 </span>
<span>$5036.42 - $4942.92 = $93.50,
Thus, the result is (B)</span>
Answer:
C. 5 degrees of freedom for the numerator and 114 for the denominator
Step-by-step explanation:
Analysis of variance (ANOVA) is utilized to examine the variations among group means within a sample.
The sum of squares represents the cumulative square of variation, which refers to the deviation of each individual value from the grand mean.
Assuming there are
groups and each group contains
individuals, the variation can be calculated using the following formulas:
This also has the property

The numerator's degrees of freedom in this case is given by
where k = 6 represents the number of groups.
The denominator's degrees of freedom in this scenario is indicated by
.
The total degrees of freedom would be
.
Thus, the appropriate answer would be 5 degrees of freedom for the numerator and 119 degrees of freedom for the denominator.
C. 5 numerator and 114 denominator degrees of freedom