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Ratling
1 month ago
11

True or False: Like the edges of a filled-in area, the endpoints of a polygon do not need to conform to snap points.

Mathematics
1 answer:
PIT_PIT [12.4K]1 month ago
8 0

Answer:

The response is "False."

Explanation:

In geometry, an area refers to the space that an object occupies. A filled area consists of lines that connect to create an "edge."

These connecting lines help define the shape or area of the object and are known as "snap points." Keep in mind that "polygons" are made up of line segments that connect at their endpoints to form a closed shape. Consequently, it must adhere to "snap points."

This clarifies the response.

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Graph a parabola whose xxx-intercepts are at x=-3x=−3x, equals, minus, 3 and x=5x=5x, equals, 5 and whose minimum value is y=-4y
AnnZ [12381]

Answer:

Vertex: (1, -4)

intercept: (-3, 0)

Step-by-step explanation:

Let's be honest, you're not here for a detailed breakdown; you simply want the answer.

HOWEVER... the vertex corresponds to the Y-axis while the intercept aligns with the X-axis.

7 0
1 month ago
A company had 80 employees whose salaries are summarized in the frequency distribution below. Find the standard deviation. A fre
PIT_PIT [12445]
The computed standard deviation is 7588.09.
7 0
1 month ago
Read 2 more answers
Margie received her store order on 12/3/16 at 4AM. She just opened one of the
Inessa [12570]

Answer:

Expiration Date: 1/17/2017

Expiration Time: 4:00am

Preparation Date: 12/3/2016

Preparation Time: 4:00am

Initial Usage Date: 12/7/2016

Detailed Breakdown:

An illustrative depiction of the question has been provided in an image format for clarity.

From the information given, it is noted that her store order arrived on 12/3/2016 at 4am, confirming that both the prep date and time are 12/3/2016 and 4am respectively. The product has a printed expiration date of 1/17/2017, logically indicating that its expiration time is also 4am, in line with the prep time; adding 24 hours leads us back to the same time on the expiration date. Furthermore, we were informed that she utilized the product on 12/7/2016, which marks the initial use date. Based on this information, we can summarize as follows:

Expiration Date: 1/17/2017

Expiration Time: 4:00am

Preparation Date: 12/3/2016

Preparation Time: 4:00am

Initial Usage Date: 12/7/2016

8 0
2 months ago
Josh bought 20 shares of Netflix at $117.98. A year later, he bought 20 more shares at $124.32. He later sold all of his shares
Leona [12618]
20*117.98 + 20*124.32 = $4846.00 

<span>$4846.00*1.02 = $4942.92 </span>

<span>40*128.48 = $5139.20 </span>

<span>0.02*5139.20 = $102.78 </span>

<span>$5139.20 - $102.78 = $5036.42 </span>

<span>$5036.42 - $4942.92 = $93.50, 
Thus, the result is (B)</span>
5 0
26 days ago
Read 2 more answers
An ANOVA procedure is applied to data obtained from 6 samples where each sample contains 20 observations. The degrees of freedom
PIT_PIT [12445]

Answer:

C. 5 degrees of freedom for the numerator and 114 for the denominator

Step-by-step explanation:

Analysis of variance (ANOVA) is utilized to examine the variations among group means within a sample.

The sum of squares represents the cumulative square of variation, which refers to the deviation of each individual value from the grand mean.

Assuming there are 6 groups and each group contains j=1,\dots,20 individuals, the variation can be calculated using the following formulas:

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

This also has the property

SST=SS_{between}+SS_{within}

The numerator's degrees of freedom in this case is given by df_{num}=df_{within}=k-1=6-1=5 where k = 6 represents the number of groups.

The denominator's degrees of freedom in this scenario is indicated by df_{den}=df_{between}=N-K=6*20-6=114.

The total degrees of freedom would be df=N-1=6*20 -1 =119.

Thus, the appropriate answer would be 5 degrees of freedom for the numerator and 119 degrees of freedom for the denominator.

C. 5 numerator and 114 denominator degrees of freedom

8 0
1 month ago
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