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ser-zykov
3 months ago
8

What is the quotient (x3 – 3x2 + 3x – 2) ÷ (x2 – x + 1)?

Mathematics
2 answers:
PIT_PIT [12.4K]3 months ago
5 0
                 x  -   2
              _______________
x^2-x+1 | x^3 - 3x^2 + 3x - 2                x^3 - x^2  +  x                        -------------- 
                       -2x^2 + 2x -2                       -2x^2 + 2x  - 2                       ------------------                                   0
Quotient = x - 2
tester [12.3K]3 months ago
5 0

We have to calculate the result of the division problem.

\frac{x^{3}-3x^{2}+3x-2}{x^{2}-x+1}

To determine the result, long division will be employed.

x^{2}-x+1)x^{3}-3x^{2}+3x-2

Initially, we quotient with x since x^{2} fits into x^{3}, x times.

Thus, we have:

x^{2}-x+1)x^{3}-3x^{2}+3x-2(x

\text{..................}x^{3}-x^{2}+x

After subtraction, we obtain:

\text{....................}-2x^{2}+2x-2

We can see that x^{2} fits into -2x^{2}, -2 times; therefore, the next addition to the quotient will be -2. This results in a final quotient of (x-2).


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3 months ago
Seventy-five cars sit on a parking lot. Thirty have stereo systems, 30 have air conditioners and 40 have sun roofs. Thirty of th
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a. 55 cars

b. 25 cars

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N(ss) = 30

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a.

To calculate how many cars possess at least one feature (N(at least one) or N(ss or ac or sr)), we apply:

N(ss or ac or sr) = N(ss) + N(ac) + N(sr) - N(ss and ac) - N(ss and sr) - N(ac and sr) + N(ss and ac and sr)

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Substituting, we find N(ss or ac or sr) = 30 + 30 + 40 - (30 + 2*15) + 15 = 55

b.

For those cars that have exactly one feature, we have:

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N(only one) = 55 - 30 = 25

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