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erik
20 days ago
12

You need to lower your debt to credit limit ratio by $1000. Your current limit is $1400. $1000 is what percent of your credit li

mit
Mathematics
You might be interested in
Write the number 0.21212121.. as a fraction let x=
AnnZ [12381]
To work with the repeating decimals, note that since there are two digits repeating, you will be using a 1 followed by two zeros, which is 100. This factor will be important for subsequent calculations.

Let’s denote the repeating decimal as x.

Thus, you can write

x = 0.212121...

Now, if you multiply this equation by 100, you can write it on top of the previous equation.
This results in:

100x = 21.212121...
x = 0.212121...

Next, set up a subtraction by taking the second equation from the first:

100x = 21.212121...
x = 0.212121...
- ----------------------------
99x = 21

Solving for x involves dividing both sides by 3:

33x = 7

Then, divide both sides by 33:

x = 7/33

Thus, we conclude that the repeating decimal 0.212121... equates to the fraction 7/33.

Answer: the fraction is 7/33
7 0
3 months ago
An engineer wishes to determine the width of a particular electronic component. If she knows that the standard deviation of all
Leona [12618]

Answer:

n=(\frac{0.539(2.2)}{0.3})^2 =15.62 \approx 16

In this scenario, the solution for n is determined to be 16 when rounded up to the closest integer

Step-by-step explanation:

The following information has been provided for this case:

\sigma = 2.2 symbolizes the population standard deviation

Confidence =0.8

ME = 0.3 signifies the preferred margin of error

The formula for the margin of error of the actual mean is given as:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

In this case, the margin of error (ME) is 0.03, and to find n, we rearrange equation (a) to get:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

With a confidence level of 80%, and the significance level being \alpha=0.2 and \alpha/2 =0.1, the critical value is z_{\alpha/2}=0.539. Plugging in these values into formula (b) results in:

n=(\frac{0.539(2.2)}{0.3})^2 =15.62 \approx 16

Thus, the solution for this situation results in n=16, rounded to the nearest whole number

5 0
1 month ago
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