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allochka39001
2 months ago
9

The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be used to find

the length of the remaining side?

Mathematics
2 answers:
Svet_ta [12.7K]2 months ago
8 0

Response: Using the Pythagorean theorem, we can set up the equation as 14^2=9^2+x^2

                                     -9^2    -9^2

Thus, our equation simplifies to

x^2=14^2-9^2

lawyer [12.5K]2 months ago
4 0

Answer:

10.7 units

Step-by-step explanation:

This is actually quite straightforward.

You will need to apply the Pythagorean Theorem formula, which is a^2+b^2=c^2, where we have a and c in this instance.

Here, c equals 14 and a equals 9, so we can substitute these values in.

(9)^2+b^2=(14)^2.

Calculating 9 squared gives us 81 and 14 squared results in 196.

To isolate b, we subtract 81 from 196 resulting in 115.

Next, we need to determine the square root of 115, which gives us b, approximately 10.7 units.

Thus, the length of the remaining side measures 10.7 units.

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Answer:

840

Step-by-step explanation:

As the arrangement matters, we apply the permutations formula to find the solution.

Permutations formula:

The count of possible arrangements of x items chosen from a total of n items is defined by this formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

For this problem:

Jose occupies the first seat.

The other four can be arranged among the remaining 7 family members. Thus

P_{(7,4)} = \frac{7!}{(7-4)!} = 840

Hence, the final answer is:

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In isosceles △ABC (AC = BC) with base angle 30° CD is a median. How long is the leg of △ABC, if sum of the perimeters of △ACD an
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Important details about isosceles triangle ABC:

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  • In isosceles triangle ABC, the sides AB and BC are equal, meaning AC=BC.
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1. Consider the right triangle ACD. The angle adjacent to side AD is 30°, which dictates that the hypotenuse AC is double the length of the opposite side CD relating to angle A.

AC=2CD.

2. Now, for right triangle BCD, the angle next to side BD is also 30°, so hypotenuse BC is twice the opposite leg CD linked to angle B.

BC=2CD.

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P_{ACD}=AC+CD+AD=2CD+CD+AD=3CD+AD;

P_{BCD}=BC+CD+BD=2CD+CD+AD=3CD+AD;

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4. If the total of the perimeters of triangles ACD and BCD is 20 cm greater than the perimeter of triangle ABC, then

P_{ACD}+P_{BCD}=P_{ABC}+20,\\ \\3CD+AD+3CD+AD=4CD+2AD+20,\\ \\6CD+2AD=4CD+2AD+20,\\ \\2CD=20.

5. Given that AC=BC=2CD, the lengths of legs AC and BC of the isosceles triangles are 20 cm.

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The fox’s speed needs to exceed that of the rabbit to successfully catch up. Thus, the required speed for the fox is expressed as 35/t + 40.

The distance separating the rabbit from the fox is 35 feet.

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Fox's speed = F

To calculate a precise speed for the fox, a specific time for the pursuit must be provided.

Let’s denote the time as t.

Recall that:

Speed = distance / time

Distance = speed × time

The distance the rabbit moves away from the fox after time t will be:

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The distance traveled by the fox after time t is: fox speed × t = F × t.

To catch the rabbit, both the fox and rabbit must cover the same distance:

Rabbit's distance at time t equals Fox's distance at that time.

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