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Basile
19 days ago
14

Find pb, if pj=14 and jb= 28

Mathematics
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2 tens and 76 ones equals
tester [12383]
It amounts to 96. I hope this was helpful.
5 0
2 months ago
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3400 dollars is placed in an account with an annual interest rate of 8.25%. How much will be in the account after 25 years, to t
Leona [12618]
=3400(1+0.0825/1)^1*25
=3400(1.0825)^25
=3400(7.2560058)
=24670.41

Hope this assists!!!
6 0
2 months ago
At a certain company, loan agents are paid based on the number of loans they close in a day. Based on company records, the numbe
Zina [12379]

Answer:

C. The mean daily salary is not above $350 per day

Step-by-step explanation:

The calculation is displayed below:

Y = a + bX

where,

Y = earnings of a randomly chosen agent

a = $150

b = $50

X = number of loans closed

Now

E(x) = (1 × 0.05) + (2 × 0.10) + (3 × 0.22) + (4 × 0.30) + (5 × 0.18) + (6 × 0.12) + (7 × 0.03)

= 3.94

Consequently,

E(y) = $150 + ($50 × 3.94)

= $347

therefore, option C is incorrect

4 0
3 months ago
Read 2 more answers
The temperature, H, in degrees Celsius, of a cup of coffee placed on the kitchen counter is given by H = f(t), where t is in min
Leona [12618]

Response:

a

    f'(t) is negative

b

 The unit is degC/min

c

At 35 minutes since the coffee was placed on the counter, the temperature is 68, and it will drop by approximately 0.75 in the next 30 seconds.

Detailed explanation:

According to the question, we are informed that

   The temperature of a cup of coffee on a counter is represented by the equation

         H= f(t)

where t indicates the time in minutes since the coffee was set on the counter.

In general, f(t)' denotes the derivative of f(t), indicating the change in temperature over time for the coffee

As the coffee rests on the counter, its temperature tends to decrease after a few minutes; thus, f(t)' is negative.

The temperature is measured in degrees Celsius while time is expressed in minutes.

Therefore, the change in temperature with respect to time, f(35)', will be given in degrees Celsius per minute (i.e., degC/min).

The question states that

        |f(35)'| = 1.5

which means the rate of temperature change after 35 minutes is 1.5.

And

         |f(35)| = 68

indicating that the coffee's temperature after 35 minutes is 67 degrees Celsius.

Subsequently, after another t= 30 seconds = \frac{30}{60}= 0.5 \ minutes the rate at which the coffee's temperature changes is

          R = |f(35)'| * t

=>        R = 1.5 * 0.5

=>        R = 0.75    

Thus

At 35 minutes since the coffee was placed on the counter, its temperature is 68 and will drop by roughly 0.75 in the next 30 seconds.

     

5 0
3 months ago
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