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Citrus2011
3 months ago
6

At time t = 0 a car moves into the passing lane to pass a slow-moving truck. The average velocity of the car from t =1tot =1+his

Mathematics
1 answer:
babunello [11.8K]3 months ago
4 0

The equation provided is:

v = [3 (h + 1)^2.5 + 580 h – 3] / 10 h

To find the instantaneous velocity when t = 1, we need to set h = 0. This presents a problem as h is in the denominator, which would make the result infinite. Instead, we should use a value for h that is nearly zero. Here, we take h as 0.0000001, so we have:

 

for t = 1

v = [3 (0.0000001 + 1)^2.5 + 580 (0.0000001) – 3] / 10 * 0.0000001

<span>v = 58.75 ft/s</span>

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