A national survey of 50,000 sixth graders asked if they know what they would like to do when they get older. Suppose you ask 350

Answer:

Find below:

Step-by-step explanation:

To determine this, we will either calculate the total cost of acquiring 40 bouquets at $2.50 each or find the single bouquet’s cost at $120.

Cost of one in pack of 40 priced at $120.

120 divided by 40 equals $3

Now, we notice that $3>$2.50

This indicates Kendra has made an error by purchasing the 40 bouquet pack at $120

Hope this helps.

The options presented are:

(1) division property of equality

(2) factoring the binomial

(3) completing the square

(4) subtraction property of equality

Response: (2) factoring the binomial

Step 1:

Step 2:

In step 2, 'a' is extracted from . Upon factoring out 'a', we divide all terms by 'a', resulting in .

Step 2 involves the binomial factorization process.

Answer: 0.12

Step-by-step explanation:

There are a total of 65 candy bars. Within this amount;

2 candy bars contain 300 to 350 calories

1 candy bar contains 350 to 400 calories

4 candy bars contain 400 to 450 calories

1 candy bar contains 450 to 500 calories

Thus, the overall ratio of candy bars with more than 300 calories is;

= (2 + 1 + 4 + 1) / 65

= 8/65

= 0.12

Answer:

a. Alpha equals 3.014 while beta equals 12.442

b. The likelihood that the data transfer duration surpasses 50ms is 0.238

c. The chance that data transfer time falls between 50 and 75 ms is 0.176

Step-by-step explanation:

a. Given the data, the mean and standard deviation for the random variable X are 37.5 ms and 21.6, respectively.

Thus, E(X)=37.5 and V(X)=(21.6)∧2  

To find alpha, we need to apply the formula:

alpha=E(X)∧2/V(X)

alpha=(37.5)∧2/21.6∧2

alpha=1,406.25 /466.56

​alpha=3.014

To determine beta, the following formula is employed:

β=  V(X) ∧2/E(X)

β=(21.6)  ∧2/37.5

β=466.56 /37.5

β=12.442

b. With E(X)=37.5 and V(X)=(21.6)∧2,  

Hence, P(X>50)=1−P(X≤50)

To find the probability of data transfer time exceeding 50ms, we use the formula:

P(X>50)=1−P(X≤50)

=1−0.762

=0.238

The chance of data transfer time exceeding 50ms is 0.238

c. With E(X)=37.5 and V(X)=(21.6)∧2,  

Thus, P(50<X<75)=P(X<75)−P(X<50)  

To find the probability that data transfer time is between 50 and 75 ms, we apply the formula:

P(50<X<75)=P(X<75)−P(X<50)

=0.938−0.762

=0.176

​

The probability that data transfer time falls between 50 and 75 ms is 0.176