Scores on an exam follow an approximately normal distribution with a mean of 76.4 and a standard deviation of 6.1 points. what i

The <span>root<span> of a numeral x represents another number that, when multiplied by itself for a specific amount of times, results in x. For instance, the square <span>root<span> of 9 is 3, given that 3 x 3 equals 9. The square <span>root<span> is the term commonly used for the second <span>root<span>. Meanwhile, the term for the third <span>root<span> is known as the cube <span>root<span>. Refer to <span>Root<span> (of a number). because then/</span> </span></span></span></span></span></span></span></span></span></span></span></span></span>

Answer:

The solution to the equation is 40

This indicates the max number of wedding invitations they can afford to send within their budget.

Step-by-step explanation:

To find the zero of the function, we set the dependent variable (here, m) to zero.

So we have;

0 = 50-1.25w

1.25w = 50

w = 50/1.25

w = 40

What implication does this have in this context?

Essentially, it means that the couple can send out invitations to a total of 40 people based on their budget.

Response:

Detailed explanation:

a) this situation has a two-tailed test

The critical value is found using the t distribution table.

α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Consulting 0.975 with df 10

The critical value obtained is 2.228

b) α = 1 - 0.95 = 0.05

1 - α/2 = 1 - 0.05/2 = 1 - 0.025 = 0.975

Consulting 0.975 with df 20

The critical value obtained is 2.086

c) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Consulting 0.995 with df 20

The critical value obtained is 2.845

d) α = 1 - 0.99 = 0.01

1 - α/2 = 1 - 0.01/2 = 1 - 0.005 = 0.995

Consulting 0.995 with df 60

The critical value obtained is 2.660

e) 1 - α = 1 - 0.01 = 0.99

Consulting 0.99 with df 10

The critical value obtained is 2.764

f) 1 - α = 1 - 0.025 = 0.975

Consulting 0.975 with df 5

The critical value obtained is 2.571

Answer:

a) Ann has a 1/3 chance of winning in the first round

b) The chance of Ann winning for the first time in the fourth round is 8/81

c) The probability that Ann's first win occurs after the fourth round is 16/81

Step-by-step explanation:

a) Each strategy is played with a probability of 1/3. Given any strategy, there’s a 1/3 chance that Bill will choose the strategy that allows Ann to win. Consequently, the probability of Ann securing a victory in the first round (or any round) is

1/3 * 1/3 + 1/3 * 1/3 + 1/3 * 1/3 = 1/9 + 1/9 + 1/9 = 1/3.

Thus, the likelihood of Ann winning the initial round is 1/3.

b) The chances of Ann winning a round stand at 1/3; therefore, her chances of not winning are 2/3. This must happen three times before her first victory. Thus, the probability that Ann's first win occurs in the fourth round is

(2/3)³ * 1/3 = 8/81.

c) The first victory happens after the fourth round if she remains unsuccessful in the first four rounds, translating to a possibility of (2/3)⁴ = 16/81.

Part a) When a page is scaled down to 80%, how much enlargement is necessary to bring it back to its original size?

Let

x---------> the percent enlargement

Given the original size is 100%

This means:

x*80%=100%

x=(100%/80%)

x=1.25--------> 1.25=(125/100)=125%

Thus,

The answer to Part a) is

The percent enlargement required is 125%

Part b) Estimate how many successive copies of a page are needed to make the final copy less than 15% of its original size.

Since the photocopy machine reduces sizes to 80% of the original

Therefore:

Copy N 1

0.80*100%=80%

Copy N 2

0.80*80%=64%

Copy N 3

0.80*64%=51.2%

Copy N 4

0.80*51.2%=40.96%

Copy N 5

0.80*40.96%=32.77%

Copy N 6

0.80*32.77%=26.21%

Copy N 7

0.80*26.21%=20.97%

Copy N 8

0.80*20.97%=16.78%

Copy N 9

0.80*16.78%=13.42%-------------> 13.42% < 15%

Therefore,

The answer to Part b) is

The necessary number of copies to achieve this is 9