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KonstantinChe
2 months ago
11

The sale price S (in dollars) of an item is given by the formula S=L−rL, where L is the list price (in dollars) and r is the dis

count rate (in decimal form).
R=1- S/L

The list price of the shirt is $30. What is the discount rate?
Mathematics
2 answers:
tester [12.3K]2 months ago
8 0

Answer:

The item's discount rate is r=1-\frac{S}{30}.

Detailed explanation:

The formula provided is S = L - rL.

Here, S stands for the sale price,

r is the discount rate,

and L is the list price.

By rearranging, we get:

S - L = -rL

L - S = rL

which can be written as

r=\frac{1}{L}(L-S)

r=1-\frac{S}{L}

To find the discount rate for a shirt listed at $30, substitute L = 30 into the equation:

r=1-\frac{S}{30}

The resulting discount rate is r=1-\frac{S}{30}.

babunello [11.8K]2 months ago
7 0

The sale price S (in dollars) of an item is calculated using the formula

S = L - rL, where L represents the list price (dollars) and r denotes the discount rate.

Rearranged, this becomes:

rL = L - S

and thus

r = \frac{L-S}{L}

which simplifies to

r = 1-\frac{S}{L}

Given the shirt's list price is $30, we will compute the discount rate accordingly.

Hence, the discount rate r equals 1-\frac{S}{30}.

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Answer:

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Cheese costs $4.40 per pound. Find the cost per kilogram. (1kg = 2.2lb)
AnnZ [12381]

Answer:

The price amounts to $9.70 per kilogram.

Step-by-step explanation:

This can be resolved using the rule of three.

In a rule of three scenario, the first step involves determining how the values are related, whether directly or inversely.

A direct relationship implies that when one measure increases, the corresponding measure also increases. In this case, cross multiplication serves as the method for the rule of three.

Alternatively, an inverse relationship indicates that an increase in one measurement causes a decrease in the other. In this scenario, line multiplication applies.

Here, the relationship is between the weight of the cheese and its cost. As the weight rises, so does the expense, representing a direct proportion.

Solution:

According to the problem, cheese is priced at $4.40 per pound. Given that each kg equals 2.2 pounds, we can deduce how many kg correspond to one pound.

1 pound - x kg

2.2 pounds - 1 kg

2.2x = 1

x = \frac{1}{2.2}

x = 0.45 kg

Given that cheese costs $4.40 for a pound, and there are 0.45 kg in one pound, we calculate the cost for 1 kg.

$4.40 - 0.45 kg

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0.45x = 4.40

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6 0
1 month ago
The number of "destination weddings" has skyrocketed in recent years. For example, many couples are opting to have their wedding
zzz [12365]

Answer:

Based on the findings, we infer that the average cost of a wedding is lower than the $30,000 that was initially suggested.

Step-by-step explanation:

The following data set is provided: (in thousands)

29100, 28500, 28800, 29400, 29800, 29800, 30100, 30600

Formula:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}

where x_i denotes data points, \bar{x} represents the mean, and n indicates the number of samples.

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{236100}{8} = 29512.5

The sum of squares of the differences equals 3408750

S.D = \sqrt{\frac{3408750}{7}} = 697.82

The population mean, μ = $30,000

The sample mean, \bar{x} = $29512.5

Sample size, n = 8

Alpha, α = 0.05

Sample standard deviation, s = $697.82

Initially, we formulate the null hypothesis and the alternative hypothesis.

H_{0}: \mu = 30000\text{ dollars}\\H_A: \mu < 30000\text{ dollars} A one-tailed t-test will be conducted for this analysis.

Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

<pinserting the="" values="" we="" derive="">

t_{stat} = \displaystyle\frac{29512.5 - 30000}{\frac{697.82}{\sqrt{8}} } = -1.975

<pnow>

t_{critical} \text{ at 0.05 level of significance, 7 degree of freedom } = -1.894

<pgiven the="" situation="">

t_{stat} < t_{critical}

<pwe do="" not="" accept="" the="" null="" hypothesis="" and="" reject="" it.="">

Thus, we conclude that the average wedding cost is indeed less than the advertised $30,000.

</pwe></pgiven></pnow></pinserting>
8 0
1 month ago
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