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lidiya
2 months ago
11

9. The purpose of statistical inference is to provide information about the.

Mathematics
1 answer:
AnnZ [12.3K]2 months ago
6 0
<span>c. demographics based on the details in the population.#9

#10</span><span>b. 81 and 18.</span>
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a golfer needs to hit a ball a distance of 500 feet, but there is a 60-foot tall tree that is 100 feet in front of the point whe
Svet_ta [12734]
We can formulate the trajectory of the parabola using the vertex form equation: y = a (x – h)^2 + k. The coordinates for the vertex are at h and k, representing the peak height, thus h = 250 and k = 120. Consequently, the equation becomes y = a (x – 250)^2 + 120. At the starting point where x = 0 and y = 0, we find a: 0 = a (0 – 250)^2 + 120, which simplifies to 0 = a (62,500) + 120, leading to a = -0.00192. The complete equation is y = -0.00192 (x – 250)^2 + 120. To determine y when x = 400, we substitute: y = -0.00192 (400 - 250)^2 + 120, yielding y = 76.8 ft. Hence, the ball clears the tree by 76.8 ft – 60 ft = 16.8 ft.
8 0
2 months ago
Mia had $22. Then she started to receive $4 a week as an allowance. She plans to save all of her money for a bicycle and draws a
AnnZ [12381]
For Mia's calculations, she should use y first because y signifies 22, while x indicates 4 dollars earned weekly.
8 0
2 months ago
Let c1(t) = eti + (sin(t))j + t3k and c2(t) = e−ti + (cos(t))j − 6t3k. Find the stated derivatives in two different ways to veri
Zina [12379]

Answer:

i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

\frac{d}{dx}(e^x) = e^x

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

\frac{d}{dx}(e^x) = e^x

\frac{d}{dx}(sinx) = cosx\\\frac{d}{dx}(cosx) = -sinx

Next, differentiate with respect to 't'

\frac{d}{dt}c_{1}+ c_{2} } = e^ t i +cost j +3t^2 k - e^-t i - sintj -18t^2 k

By factoring out i, j, and k terms, we arrive at:

\frac{d}{dt}(C_{1} +C_{2} ) = i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

7 0
2 months ago
Mark and robyn used base-ten blocks to show that 200 is 100 times as much as 2. Whose model makes sense whose model is nonsense?
babunello [11817]

Answer:

Robyn's model is logical, while Mark's is illogical.

Step-by-step explanation:

This question doesn't require calculations. What we need to do is analyze each model logically.

Mark's

Mark's representation indicates 20 instead of 2, which signifies that 200 is ten times greater than 20, making it nonsensical.

Robyn's

Robyn's representation displays 2, suggesting that 200 is 100 times greater than 2, which is not only accurate but also reasonable since 100 * 2 equals 200.

4 0
2 months ago
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