All categories

10 days ago

Tempestt graphs a function that has a maximum located at (-4, 2). Which could be her graph?

Mathematics

1 answer:

Zina [3.9K]10 days ago

3 0

Answer:

This is my interpretation

Step-by-step explanation:

Consider the function as a parabola.

Since this function has a peak, it indicates the parabola opens downward.

The peak occurs at (-4,2), placing it in the second quadrant.

The illustration might resemble the one shown below.

I hope this is useful to you

Please consider marking my response as brainalist

8 0

13 days ago

Read 2 more answers

Last year, sales at a book store increased from $5,000 to $10,000. This year, sales decreased to $5,000 from $10,000. What perce

Svet_ta [4321]

1. 200% =2
5000 multiplied by 2 equals 10000
2.50% = 0.5
10000 multiplied by 0.5 equals 5000

4 0

8 days ago

Read 2 more answers

In three hours, Company ABC can make X ball bearings. Company DEF can make X ball bearings in 4 hours. Company GHI can make X ba

AnnZ [3877]

Answer:

X ball bearings can be produced in 1 hour and 20 minutes

Step-by-step explanation:

Proportions

Proportions serve as an essential method for solving various common challenges. We understand that:

Company ABC manufactures X ball bearings in 3 hours.

Company DEF produces X ball bearings in 4 hours.

Company GHI generates X ball bearings in 6 hours.

In a single hour, each company is capable of producing:

ABC: X/3 ball bearings

DEF: X/4 ball bearings

GHI: X/6 ball bearings

By collaborating, they can produce

$\displaystyle \frac{X}{3}+\frac{X}{4}+\frac{X}{6}$

ball bearings. Operating together

$\displaystyle \frac{4X+3X+2X}{12}=\frac{9X}{12}=\frac{3X}{4}$

If their output is 3/4 of a ball bearing in one hour, then it will take

$\displaystyle \frac{4}{3}$ hours to create one complete ball bearing. This translates to 1 hour and 20 minutes.

X ball bearings can be produced in 1 hour and 20 minutes

8 0

17 days ago

Ollie has installed security lights on the side of his house that are activated by a sensor. The sensor is located at point C di

Leona [4166]

Result:

20.19°

Detailed explanation:

Refer to the attached diagram related to the question. We need to determine <CAB

Utilizing the sine rule on triangle ABC:

$\frac{4.5}{sin15^0} = \frac{6}{sin$

cross-multiply

$4.5 * sin$

Thus, the angle <CAB measures 20.19°

8 0

12 days ago

A certain pen has been designed so that true average writing lifetime under controlled conditions (involving the use of awriting

tester [3916]

Answer:

a) Null hypothesis: $\mu \geq 10$

Alternative hypothesis: $\mu < 10$

b) $p_v =P(t_{17}$

Given that the p-value is lower than the significance threshold in this situation, we have sufficient grounds to reject the null hypothesis.

c) $p_v =P(t_{17}$

In this case, since the p-value exceeds the significance threshold, we have adequate evidence to FAIL to reject the null hypothesis.

d) $p_v =P(t_{17}$

Here again, with the p-value being less than the significance level, we can reject the null hypothesis.

Step-by-step explanation:

1) Provided data and references

$\bar X$ represents the average of the samples

$s$ denotes the standard deviation of the samples

$n=18$ indicates the number of samples

$\mu_o =10$ is the value we are examining

$\alpha$ defines the significance level for the test.

t represents the specific statistic of interest

$p_v$ indicates the p-value relevant to the test (the variable of concern)

Define the null and alternative hypotheses.

To assess if the true mean is at least 10 hours, we must set up a hypothesis:

Part a

Null hypothesis: $\mu \geq 10$

Alternative hypothesis: $\mu < 10$

If we consider the sample size being less than 30 and the population deviation unknown, it’s more appropriate to use a t-test to compare the actual mean with the reference value, calculated as:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Part b

In this scenario t=-2.3, $\alpha=0.05$

Initially, we need to calculate the degrees of freedom $df=n-1=18-1=17$

Since this is a left-tailed test, the p-value is determined by:

$p_v =P(t_{17}$

In this instance, with the p-value being less than the significance level, we have sufficient evidence to reject the null hypothesis.

Part c

For this situation t=-1.8, $\alpha=0.01$

We need to find the degrees of freedom $df=n-1=18-1=17$

For the left-tailed test, the p-value is given by:

$p_v =P(t_{17}$

In this case, since the p-value is above the significance level, we have enough grounds to FAIL to reject the null hypothesis.

Part d

For this case t=-3.6, $\alpha=0.05$

Firstly, we find the degrees of freedom $df=n-1=18-1=17$

Since we are conducting a left-tailed test, the p-value is calculated as:

$p_v =P(t_{17}$

Here, with the p-value being lower than the significance threshold, we can reject the null hypothesis.

5 0

6 days ago