Let's denote the orbital period of planet X as T and its average distance from the sun as A. For planet Y, let its orbital period be T_1, implying that if planet Y's mean distance from the sun is twice that of planet X:
This indicates that the orbital period for planet Y increases by a factor of 
Answer:
The hawk releases the prey from a height of 4 meters.
It takes the prey 4 seconds to reach the ground.
Step-by-step explanation:
The equation gives insights about the height of the prey at any time starting from the moment it is dropped. Thus, to determine the drop height, we evaluate the expression at time equals zero (the drop moment). This answers the first question:
To ascertain when the prey touches the ground, we set "h" to zero (height of zero) and solve for "t".
This results in a quadratic equation that can be solved via the quadratic formula:
Since negative time values are impractical, we select the positive 4 (4 seconds)
Applying the cosine law, we can determine:
<span>c</span>²<span> = a</span>²<span> + b</span>²<span> - 2abcos(C) </span>
<span>where: </span>
<span>a, b, and c represent the sides of the triangle and C indicates the angle opposite to side c</span>
<span>Thus, we have:</span>
<span>150</span>²<span> = 240</span>²<span> + 200</span>²<span> - 2(240)(200)cos(C) </span>
<span>Now we solve for C</span>
<span>22,500 = 57,600 + 40,000 - 96,000cos(C) </span>
<span>22,500 - 57,600 - 40,000 = -96,000cos(C)
</span>-75,100=-96,000cos (C)
cos (C)=0.7822916
C=arc cos(0.7822916)→ C=38.53°
<span>Therefore, the direction the captain should head towards island B is
180 - 38.53 </span><span>= 141.47 degrees</span>
You may either multiply the numbers or the place value, and both methods will yield the same answer.
(2 thousands, 7 tens) multiplied by 10 results in
... (20 thousands, 70 tens)
or
... (2 ten-thousands, 7 hundreds)
An even function can be reflected over the y-axis and still remain unchanged.
Example: y=x^2
On the other hand, an odd function can be reflected around the origin and also remains unchanged.
Example: y=x^3
A straightforward method to determine this is:
if f(x) is even, then f(-x)=f(x)
if f(x) is odd, then f(-x)=-f(x)
Hence, for an even function
substitute -x in for each and check for equivalence
make sure to fully expand the expressions
g(x)=(x-1)^2+1=x^2-2x+1+1=x^2-2x+2 is the original expression
g(x)=(x-1)^2+1
g(-x)=(-x-1)^2+1
g(-x)=(1)(x+1)^2+1
g(-x)=x^2+2x+1+1
g(-x)=x^2+2x+2
Not the same, as the original contains -2x
Therefore, it is not even
g(x)=2x^2+1
g(-x)=2(-x)^2+1
g(-x)=2x^2+1
It matches, hence it is even
g(x)=4x+2
g(-x)=4(-x)+2
g(-x)=-4x+2
Not equivalent, thus not even
g(x)=2x
g(-x)=2(-x)
g(-x)=-2x
Not equal, therefore not even
g(x)=2x²+1 is the confirmed even function.
