Answer:
Given Data:
myBytes BYTE 10h, 20h, 30h, 40h
myWords WORD 3 DUP(?), 2000h
myString BYTE "ABCDE"
From the supplied information, we can derive that:
(a). a. EAX = 1
b. EAX = 4
c. EAX = 4
d. EAX = 2
e. EAX = 4
f. EAX = 8
g. EAX = 5
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