Answer:
The range of cheerleaders' heights lies within the interval [58, 74)
It includes all real numbers from 58 inches and above, but below 74 inches.
Step-by-step explanation:
we have

Separate the combined inequality into two distinct inequalities
-----> inequality A
-----> inequality B
Solve inequality A

Subtract 28 from both sides

Split by 4 on both sides

Reformulate

Address inequality B

Subtract 28 from both sides

Split by 4 on both sides

consequently
The height range of the cheerleaders is the interval [58, 74)
It consists of every real number starting from 58 inches and less than 74 inches
Answer:
a) Null hypothesis:
Alternative hypothesis:
b)
(1)
Where
c)
d) In this scenario, we notice that
thus the conclusion for this case would indicate
Step-by-step explanation:
Information provided
denote the number of men possessing smartphones
signify the number of women possessing smartphones
group of men sampled
group of women sampled
symbolize the proportion of men with smartphones
symbolize the proportion of women with smartphones
denote the pooled estimate of p
z would denote the test statistic
signify the value
Part a
The objective is to evaluate if there is a disparity in smartphone ownership between men and women; the hypothesis statements would be:
Null hypothesis:
Alternative hypothesis:
Part b
The statistic relevant to this case is expressed as:
(1)
Where
Part c
By substituting the provided information, we find:
Part d
In this instance, it is evident that
thus the conclusion for this case would seem
Step-by-step explanation:
Tracie's bus moves towards home at an average pace of one-half mile for every minute.
Option D is indeed correct, as it ensures that the post's point is equidistant from the ground, maintaining a perpendicular angle at two points on the surface.
Answer:
Area = 200 + 50 + x
Step-by-step explanation:
Given
Length = 20
Width = 30
Side Walk = x
Required
Find the total area.
To find this, we have to add the length of the sidewalk to the dimensions of the garden.
This results in:
Length = 20 + x.
Width = 30 + x
So, the area now becomes.
Area = (20 + x)(30 + x)
Area = 600 + 20x + 30x + x²
Area = 200 + 50 + x²