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padilas
1 month ago
7

The flowchart below shows the three generations of a cross between a pea plant that has yellow pods and a pea plant that has gre

en pods. Green pods are the dominant trait. The flowchart is missing the labels that describe the traits.
In which squares should the phrase “Green pods” appear?

1.A and D
2.B and E
3.A,C and D
4.A,B,C,D and E

Biology
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Drag each tile to the correct box. Explain the process in which hormones secreted by the pancreas function with respect to incre
s2008m [2378]

Respuesta:

El orden correcto es:

  1. Gran cantidad de glucosa en la sangre, enviando señales hacia el páncreas.  
  2. Síntesis de hormonas por células beta.
  3. Unión de hormonas con receptores en el hígado.
  4. Ingesta de moléculas de glucosa de la sangre por transportadores específicos.
  5. Liberación de hormonas desde los receptores

Explicación:

  • El páncreas produce dos hormonas clave para la regulación de los niveles de glucosa en la sangre.
  • Las dos hormonas, glucagón e insulina, aumentan y disminuyen el azúcar en la sangre respectivamente.
  • La insulina reduce la glucosa en sangre al estimular las células del cuerpo para que aumenten la ingesta de glucosa.
  • El cerebro detecta la alta/baja glucosa en sangre y, a continuación, envía señales al páncreas para iniciar la síntesis de insulina o glucagón por las células beta.
  • Estas hormonas se unen a receptores en las células del cuerpo; en las células hepáticas, en el caso de la insulina.
  • Los receptores inician la señalización celular que facilita la entrada o salida de glucosa dentro o fuera de las células del cuerpo.
4 0
2 months ago
Read 2 more answers
In a sample of 2,400 people, 1,482 were found to have the dominant (taster) phenotype. Assuming that the population is in Hardy-
Tresset [2298]

Answer:

1128.

Explanation:

The phenotype for dominant tasters is 1482.

The phenotype for recessive tasters = 2400 – 1482 = 918.

Recessive phenotypes = 2400 – 1482 = 918.

The frequency of the recessive phenotype = q² = 918 / 2400 = 0.38.

The frequency of the recessive allele q = √0.38 = 0.62.

For the dominant allele frequency, p = 1-q = 1- 0.62 = 0.38.

The heterozygous frequency =  2pq = 2 × 0.38 × 0.62 = 0.47.

The number of heterozygous individuals within the population = 0.47 × 2400 = 1128.

Thus, the result is 1128.

5 0
4 months ago
If high amounts of sulfanilamide are in the presence of an enzyme whose substrate is paba, what outcome is expected?
lana [2441]
In situations where there are elevated levels of sulfanilamide alongside an enzyme with paba as its substrate, the enzyme's activity will be inhibited by the sulfanilamide, leading to a cessation of its function. Hope this clarifies your question. Have a great day.
3 0
2 months ago
The type of plant cell that provides support without interfering with growth and is familiar as the "strings in celery" is a
lana [2441]
Une cellule végétale qui apporte un soutien sans entraver la croissance, souvent reconnue sous le terme de "fibres dans le céleri", est appelée une cellule collenchyme.
7 0
4 months ago
James is making models of plant and animal cells using objects supplied by his teacher to represent organelles. For one cell, he
Rainbow [2354]
The answer is B. Animal cells lack a cell wall, while the shoebox signifies the cell wall. I hope this information has been helpful![[TAG_1]] 
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