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zepelin
7 days ago
14

If 15% of the customer's total is $22.05, then the customer's total is

Mathematics
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A recipe calls for One-fourth cup of broth. The largest volume-measuring tool that Tabitha has is a teaspoon. She knows that the
babunello [11817]

Answer:Tabitha will require 12 teaspoons.

Explanation:

According to the question, Tabitha possesses a teaspoon as her largest volume-measuring tool, and she needs to utilize one-fourth cup of broth.

Knowing that 1 cup equals 16 tablespoons and that there are 3 teaspoons in each tablespoon.

From the given data, we can compute that 16 tablespoons corresponds to (3*16)= 48 teaspoons.

Thus, 1 cup = 48 teaspoons.

Substituting these values, we find that 1/4 cup = 48/4 = 12 teaspoons.

5 0
1 month ago
Jane is one of 50 students to take a standardized math test that includes 100 multiple choice questions. If she has the highest
Svet_ta [12734]
Response: 87%
Solution:
87 correct answers out of 100 = 87/100 = 0.87 = (convert to percentage by shifting the decimal place two positions to the right) 87%
8 0
2 months ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [12365]
\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
2 months ago
Read 2 more answers
2. What is the 44th decimal digit in the decimal representation of 1/11 which equals 0.0909090909
tester [12383]
9. Observing the pattern, the decimal digit at position n is 9 when n is even and 0 when n is odd. Because 44 is an even number, the 44th digit after the decimal point is 9.
6 0
3 months ago
The table represents the equation y = 2 – 4x. A 2-column table with 5 rows. The first column is labeled x with entries negative
tester [12383]

The missing value associated with x=-1 is y=6

Explanation:

The provided equation for the table is y=2-4x

This table consists of 2 columns and 5 rows.

<pconsequently it="" states="">

x       y

-2      10

-1       ---

0        2

1        -2

2       -6

To find the value for y when x=-1

The value of y can be ascertained by substituting x=-1 into the equation y=2-4x

<pthus we="" determine="">

y=2-4(-1)

<pmultiplying the="" term="" within="" brackets="" yields="">

y=2+4

<psumming the="" terms="" we="" find="">

y=6

<pso the="">value of y when x=-1 is 6.

Hence, the value for x=-1 is y=6

</pso></psumming></pmultiplying></pthus></pconsequently>
7 0
3 months ago
Read 2 more answers
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