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2 months ago

If LCM of two prime numbers a and b (a>b) is 783 , then the value of 2ab-3a is?

Mathematics

1 answer:

Svet_ta [12.7K]2 months ago

8 0

Answer:

LCM(a, b) signifies the least common multiple of the two numbers a and b.

LCM(a,b) = a*b/GCF(a,b)

Where GCF(a,b) represents the greatest common factor of a and b.

The smallest common multiple for two prime numbers is merely the product of those primes (because their only shared factor is 1).

LCM(a,b) = a*b = 783.

To determine the values of a and b, we can divide 783 by various primes to find when the result is an integer:

(Skipping 2 as 783 is odd, I'll start with 3)

783/3 = 261

Thus, the two primes identified are 3 and 261.

Given that a > b, we have:

a = 261

b = 3.

Calculating 2*a*b - 3*a gives 2*261*3 - 3*261 = 261*3*(2 - 1) = 261*3 = 783.

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If LCM of two prime numbers a and b (a>b) is 783 , then the value of 2ab-3a is?​

If LCM of two prime numbers a and b (a>b) is 783 , then the value of 2ab-3a is?